Question
Download Solution PDFConsider Op-Amp biasing voltage as ±15V. The threshold voltages for Schmitt trigger is :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
A Schmitt trigger is a comparator circuit with hysteresis, meaning it has two distinct threshold voltages: one for the rising input (upper threshold) and one for the falling input (lower threshold).
The threshold voltages are determined by the positive feedback network. For a non-inverting Schmitt trigger configuration using an op-amp, the threshold voltage is given by:
\( V_T = V_{out} \cdot \frac{R_2}{R_1 + R_2} + V_{ref} \cdot \frac{R_1}{R_1 + R_2} \)
Given:
R1 = 2 kΩ, R2 = 1 kΩ
Vout = ±15V (op-amp saturation levels)
Vref = 3V (battery at non-inverting terminal)
Calculation:
Feedback fraction = R2 / (R1 + R2) = 1 / (2 + 1) = 1/3
Battery contribution = Vref · (R1 / (R1 + R2)) = 3 · (2 / 3) = 2V
Case 1: When Vout = +15V:
\( V_{UTP} = \frac{15}{3} + 2 = 5 + 2 = 7V \)
Case 2: When Vout = -15V:
\( V_{LTP} = \frac{-15}{3} + 2 = -5 + 2 = -3V \)
Final Answer:
Threshold voltages are: 7V (upper), −3V (lower)
Correct Option: 3) 7V, −3V
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