Question
Download Solution PDFC1, C2 and C3 can do a work alone in 10, 12 and 15 days respectively. All three of them began the work together but C2 left 2 days before the completion of the work. In how many days was the work completed?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven
C1's rate = 1/10 per day, C2's rate = 1/12 per day, C3's rate = 1/15 per day
Formula:
Total time = total work/combined rate of work
Solution:
⇒ The combined rate of C1, C2, and C3 = 1/10 + 1/12 + 1/15 = 1/4 per day
⇒ Since C2 left 2 days earlier, the work done in those 2 days = 2 (1/10 + 1/15) = 1/3
⇒ Remaining work = 1 - 1/3 = 2/3
⇒ Time to complete the remaining work = 2/3 / 1/4 = 8/3 days
⇒ Total time = 2 + 8/3 = 14/3 days
Therefore, the work was completed in (14/3) days.
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