Question
Download Solution PDFAn object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. The magnification is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Convex mirror:
- The mirror in which the rays diverges after falling on it is known as the convex mirror.
- Convex mirrors are also known as a diverging mirror.
- The focal length of a convex mirror is positive according to the sign convention.
- Mirror Formula: The following formula is known as the mirror formula:
\(\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\)
where f is focal length v is the distance of the image from the mirror, and u is the distance of the object from the mirror.
Linear magnification (m):
- It is defined as the ratio of the height of the image (hi) to the height of the object (ho).
\(m = \frac{{{h_i}}}{{{h_o}}}\)
- The ratio of image distance to the object distance is called linear magnification.
\(m = \frac{{image\;distance\;\left( v \right)}}{{object\;distance\;\left( u \right)}} = - \frac{v}{u}\)
- A positive value of magnification means a virtual and erect image.
- A negative value of magnification means a real and inverted image.
CALCULATION:
- Given - Object distance (U) = -10 cm and Focal length (f) = 15 cm
- The mirror formula is given by
\(\Rightarrow \frac{1}{f} =\frac{1}{V}+\frac{1}{U}\)
\(\Rightarrow\frac{1}{15} =\frac{1}{V}-\frac{1}{10}\)
\(\Rightarrow\frac{1}{V}=\frac{1}{10}+\frac{1}{15}\)
\(\Rightarrow V=\frac{25}{150} = 6cm\)
- The magnification of a mirror is
\(m=-\frac{V}{U}\)
\(\Rightarrow m=-\frac{V}{U} =-\frac{6 cm }{-10 cm} =+0.6\)
- The magnification of the object is + 0.6.
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