Question
Download Solution PDFAn adiabatic heat exchanger is used to heat cold water at 15°C entering at a rate of 5 kg/s by hot air at 90°C entering also at rate of 5 kg/s. If the exit temperature of hot air is 20°C, the exit temperature of cold water is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
By usimg equilibrium of heat exchanger, we know that,
Heat loss by Hot air = Heat gain by cold water
\({\left( {m{C_p}\Delta T} \right)_{Air}} = {\left( {m{C_p}\Delta T} \right)_{water}}\)
Calculation:
Given:
For air:
Ti = 90°C, To = 20°C, m = 5 kg/s, Cp = 1 kJ/kgK
For water:
Ti = 15°C, To = ?, m = 5 kg/s, Cp = 4.2 kJ/kgK
⇒ 5 × 1 × (90 – 20) = 5 × 4.2 × (Tf – 15)
⇒ Tf = 31.6° CLast updated on Apr 14, 2023
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