ABDC is a parallelogram in which diagonals AD and BC intersect at O. AE and DF are perpendicular on BC at E and F, respectively. Which of the following is not true?

This question was previously asked in
SSC CGL Previous Paper 47 (Held On: 6 June 2019 Shift 2)
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  1. ΔADC ≅ ΔABD
  2. ΔAOE ≅ ΔDOF
  3. ΔABC ≅ ΔDCB
  4. ΔAEB ≅ ΔDFC

Answer (Detailed Solution Below)

Option 1 : ΔADC ≅ ΔABD
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Detailed Solution

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F1 V.G D.K 30.09.2019 D 1

As we know,

In quadrilateral opposite sides are parallel and equal and its diagonals bisect each other.

Go through the option (1)

In ΔADC and In ΔABD

⇒ AC = DB(Opposite sides)

⇒ AD = AD(Common)

⇒ ∠ACD = ∠ABD      (Opposite angles)

Now, we can say ΔACD ≅ ΔDBA not ΔADC ≅ ΔABD

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