Question
Download Solution PDFABCD is an isoceles trapezium such that AD||BC, AB = 5 cm, AD = 8 cm and BC = 14 cm. What is the area (in cm2) of trapezium?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFrom the above figure Using Pythagoras theorem in triangle AOB
⇒ AB2 = BO2 + OA2
⇒ 52 = 32 + OA2
⇒ OA = 4cm Which is equivalent to the height of the trapezium
⇒ Area = 1/2 × (height) × (sum of parallel sides)
⇒ Area = 1/2 × 4 × (8 + 14) = 44
∴ The area is 44 cm2
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