A source having internal impedance of (9 + j12) Ω is to deliver maximum power to a resistive load. The load resistance should be

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ESE Electronics 2010 Paper 1: Official Paper
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  1. 9 Ω
  2. 12 Ω
  3. 15 Ω
  4. 21 Ω

Answer (Detailed Solution Below)

Option 3 : 15 Ω
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Detailed Solution

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Concept: 

When load impedance is the complex conjugate of internal impedance then maximum power is transferred to the load because net reactance will be zero, so total reactive power will be zero also.

\({Z_L} = Z_s^*\)

26 June 1

Load variable

The load impedance for maximum power transfer

RL and XL are variable

RL = RS

XL = -XS

ZL = ZS*

RL only varied and

XL = Constant

RL =√(RS2 + (XL + XS)2)

RL only varied and

XL = 0

RL =√(RS2 + XS2)

 

Calculation:

Zin = 9 + j 12 Ω

To deliver maximum power:

\({R_L} = \left| {{Z_{TH}}} \right|\)

\( = \sqrt {81 + 144} \)

RL = 15 Ω

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