Question
Download Solution PDFA hydrated solid X on heating initially gives a monohydrated compound Y. Y upon heating above 373 K leads to an anhydrous white powder Z. X and Z, respectively, are:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The reaction is given below:
Na2 CO3.10H2O ⟶ Na2 CO3.H2O + 9H2O
(X) (Y)
Na2 CO3.H2O ⟶ Na2 CO3 + H2O
(Y) (Z)
Here, X represents Washing soda
Y represents Washing soda (monohydrated)
and Z represents Soda ash
When washing soda is heated which undergoes dehydrogenation to form washing soda. Then again heated above 373 K to form sodium carbonate powder with very less water content that is soda ash.
Thus, the required X and Z are Washing soda and soda ash respectively.Last updated on May 23, 2025
-> JEE Main 2025 results for Paper-2 (B.Arch./ B.Planning) were made public on May 23, 2025.
-> Keep a printout of JEE Main Application Form 2025 handy for future use to check the result and document verification for admission.
-> JEE Main is a national-level engineering entrance examination conducted for 10+2 students seeking courses B.Tech, B.E, and B. Arch/B. Planning courses.
-> JEE Mains marks are used to get into IITs, NITs, CFTIs, and other engineering institutions.
-> All the candidates can check the JEE Main Previous Year Question Papers, to score well in the JEE Main Exam 2025.