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A cylindrical candle, 14 cm in diameter and length 2 cm is melted to form a cuboid candle of dimensions 7 cm × 11 cm × 2 cm. How many cuboidal candles can be obtained?

This question was previously asked in
SSC CHSL Exam 2024 Tier-I Official Paper (Held On: 11 Jul, 2024 Shift 4)
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  1. 4
  2. 3
  3. 2
  4. 5

Answer (Detailed Solution Below)

Option 3 : 2
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Detailed Solution

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Given:

Diameter of cylindrical candle = 14 cm

Height of cylindrical candle = 2 cm

Dimensions of cuboid candle = 7 cm × 11 cm × 2 cm

Formula used:

Volume of cylinder = πr2h

Volume of cuboid = l × b × h

Number of cuboidal candles = Volume of cylinder / Volume of cuboid

Calculations:

Radius of cylinder (r) = 14 ÷ 2 = 7 cm

Volume of cylinder = π × 72 × 2 = 22/7 × 49 × 2 = 308 cm3

Volume of cuboid = 7 × 11 × 2 = 154 cm3

⇒ Number of cuboidal candles = 308 ÷ 154

⇒ Number of cuboidal candles = 2

∴ 2 cuboidal candles can be obtained.

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Last updated on Jul 22, 2025

-> The Staff selection commission has released the SSC CHSL Notification 2025 on its official website.

-> The SSC CHSL New Application Correction Window has been announced. As per the notice, the SCS CHSL Application Correction Window will now be from 25.07.2025 to 26.07.2025.   

-> The SSC CHSL is conducted to recruit candidates for various posts such as Postal Assistant, Lower Divisional Clerks, Court Clerk, Sorting Assistants, Data Entry Operators, etc. under the Central Government. 

-> The SSC CHSL Selection Process consists of a Computer Based Exam (Tier I & Tier II).

-> To enhance your preparation for the exam, practice important questions from SSC CHSL Previous Year Papers. Also, attempt SSC CHSL Mock Test.  

->UGC NET Final Asnwer Key 2025 June has been released by NTA on its official site

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