Question
Download Solution PDFA carrier is modulated to a depth of 40%. The percentage increase in the transmitted power is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The total transmitted power for an AM system is given by:
\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)
Pc = Carrier Power
μ = Modulation Index
Analysis:
When the carrier is not modulated, i.e. modulation index = 0, the transmitted power is the carrier power only, i.e.
Pt = PC
When modulated with a modulation index of 40%, the total power is calculated as:
\({P_t} = {P_c}\left( {1 + \frac{{{0.4^2}}}{2}} \right)\)
The percentage increase in power will be:
\(=\frac{{P_c}\left( {1 + \frac{{{0.4^2}}}{2}} \right)-P_c}{P_c}\times 100\)
\(=\frac{0.4^2}{2}\times 100~\%\)
= 8 %
Last updated on May 30, 2025
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