Pie Chart MCQ Quiz - Objective Question with Answer for Pie Chart - Download Free PDF
Last updated on Jul 21, 2025
Latest Pie Chart MCQ Objective Questions
Pie Chart Question 1:
Comprehension:
The pie chart shows the percentage distribution of quantity of milk in five different containers [A, B, C, D and E].
Note - Ratio of milk and water in container A, B, C, D and E is 3 : 1, 5 : 2, 7 : 2, 5 : 3 and 4 : 1 respectively. Quantity of water in container E is 5 litres.
Difference between milk in container C and D is x and difference between water in container C and D is y. If [x + y] litres milk is added to container E then find the percentage of water in container E is now?
Answer (Detailed Solution Below)
Pie Chart Question 1 Detailed Solution
Common Calculation
Quantity of water in container E is 5 litres.
Quantity of milk in container E is 5 × 4 = 20
So, 10% = 20
So, 100% = 20 × 10 = 200
Quantity of milk in container A is 200 × 12/100 = 24
Quantity of water in container A is 24 × 1 /3 = 8
Similarly, we can calculate others containers values.
|
Container |
Quantity of Milk |
Quantity of water |
|
A |
24 |
8 |
|
B |
60 |
24 |
|
C |
56 |
16 |
|
D |
40 |
24 |
|
E |
20 |
5 |
Calculation
From data:
Milk: C = 56, D = 40
⇒ x = 16
Water: C = 16, D = 24
⇒ y = 8
→ x + y = 24L milk added to container E
E was: Milk = 20, Water = 5
Now: Milk = 20 + 24 = 44
Water = 5
Total = 49
% Water = (5 / 49) × 100 ≈ 10.2%
Pie Chart Question 2:
Comprehension:
The pie chart shows the percentage distribution of quantity of milk in five different containers [A, B, C, D and E].
Note - Ratio of milk and water in container A, B, C, D and E is 3 : 1, 5 : 2, 7 : 2, 5 : 3 and 4 : 1 respectively. Quantity of water in container E is 5 litres.
Ratio of milk and water in container F is 8:5. 20% mixture from container F mixed with container A, now difference between milk and water in container A is 22 litres. Find the initial difference milk and water in container F?
Answer (Detailed Solution Below)
Pie Chart Question 2 Detailed Solution
Common Calculation
Quantity of water in container E is 5 litres.
Quantity of milk in container E is 5 × 4 = 20
So, 10% = 20
So, 100% = 20 × 10 = 200
Quantity of milk in container A is 200 × 12/100 = 24
Quantity of water in container A is 24 × 1 /3 = 8
Similarly, we can calculate others containers values.
|
Container |
Quantity of Milk |
Quantity of water |
|
A |
24 |
8 |
|
B |
60 |
24 |
|
C |
56 |
16 |
|
D |
40 |
24 |
|
E |
20 |
5 |
Calculation
Ratio of milk : water in container F = 8 : 5
→ Total parts = 13
⇒ Milk = 8x, Water = 5x
20% of container F is taken and mixed into container A
⇒ Quantity taken = 20% of (13x) = 2.6x
→ Milk added = (8/13) × 2.6x = 1.6x
→ Water added = (5/13) × 2.6x = 1x
Container A (before mixing):
Milk = 24
Water = 8
After adding from F:
Milk = 24 + 1.6x
Water = 8 + 1x
Final difference between milk and water in container A = 22 litres
So:
(24 + 1.6x) − (8 + 1x) = 22
Or, 0.6x = 6
⇒ x = 10
Initial difference in container F:
Milk = 8x = 80
Water = 5x = 50
⇒ Difference = 80 – 50 = 30 litres
Pie Chart Question 3:
Comprehension:
The pie chart shows the percentage distribution of quantity of milk in five different containers [A, B, C, D and E].
Note - Ratio of milk and water in container A, B, C, D and E is 3 : 1, 5 : 2, 7 : 2, 5 : 3 and 4 : 1 respectively. Quantity of water in container E is 5 litres.
From container D, 25% mixture is taken out and same amount water is added. Then the process repeat once more time. Find the approximate water percentage now?
Answer (Detailed Solution Below)
Pie Chart Question 3 Detailed Solution
Common Calculation
Quantity of water in container E is 5 litres.
Quantity of milk in container E is 5 × 4 = 20
So, 10% = 20
So, 100% = 20 × 10 = 200
Quantity of milk in container A is 200 × 12/100 = 24
Quantity of water in container A is 24 × 1 /3 = 8
Similarly, we can calculate others containers values.
|
Container |
Quantity of Milk |
Quantity of water |
|
A |
24 |
8 |
|
B |
60 |
24 |
|
C |
56 |
16 |
|
D |
40 |
24 |
|
E |
20 |
5 |
Calculation
Initial D: Milk = 40, Water = 24, Total = 64
Remove 25% → 16 litres
Milk removed = 25% of 40 = 10
Water removed = 25% of 24 = 6
Left = 30 milk, 18 water
Add 16L water ⇒ Water = 18 + 16 = 34
Now: Milk = 30, Water = 34
Remove 25% again of new total (64)
25% of 64 = 16L
Milk removed = 25% of 30 = 7.5
Water removed = 25% of 34 = 8.5
Left = 30 – 7.5 = 22.5 milk, water = 34 – 8.5 = 25.5
Add 16L water ⇒ Water = 25.5 + 16 = 41.5
Now: Milk = 22.5, Water = 41.5
Total = 64
% Water = (41.5 / 64) × 100 ≈ 64.84% = 65%
Pie Chart Question 4:
Comprehension:
The pie chart shows the percentage distribution of quantity of milk in five different containers [A, B, C, D and E].
Note - Ratio of milk and water in container A, B, C, D and E is 3 : 1, 5 : 2, 7 : 2, 5 : 3 and 4 : 1 respectively. Quantity of water in container E is 5 litres.
50% mixture of Container A and 40% of container B is taken and mixed with the beaker E. Find the ratio of milk and water in the beaker E now?
Answer (Detailed Solution Below)
Pie Chart Question 4 Detailed Solution
Common Calculation
Quantity of water in container E is 5 litres.
Quantity of milk in container E is 5 × 4 = 20
So, 10% = 20
So, 100% = 20 × 10 = 200
Quantity of milk in container A is 200 × 12/100 = 24
Quantity of water in container A is 24 × 1 /3 = 8
Similarly, we can calculate others containers values.
|
Container |
Quantity of Milk |
Quantity of water |
|
A |
24 |
8 |
|
B |
60 |
24 |
|
C |
56 |
16 |
|
D |
40 |
24 |
|
E |
20 |
5 |
Calculation
From A
→ 50% of 24 milk = 12,
50% of 8 water = 4
From B
→ 40% of 60 milk = 24,
40% of 24 water = 9.6
From E
→ Milk = 20, Water = 5
Total Milk = 12 + 24 + 20 = 56
Total Water = 4 + 9.6 + 5 = 18.6
Ratio (Milk : Water) = 56 : 18.6
→ 280 : 93
Pie Chart Question 5:
Comprehension:
The pie chart shows the percentage distribution of quantity of milk in five different containers [A, B, C, D and E].
Note - Ratio of milk and water in container A, B, C, D and E is 3 : 1, 5 : 2, 7 : 2, 5 : 3 and 4 : 1 respectively. Quantity of water in container E is 5 litres.
If 40% mixture from container B taken out and 20 litres milk is added then difference between milk and water in mixture is x. Find the value of x?
Answer (Detailed Solution Below)
Pie Chart Question 5 Detailed Solution
Common Calculation
Quantity of water in container E is 5 litres.
Quantity of milk in container E is 5 × 4 = 20
So, 10% = 20
So, 100% = 20 × 10 = 200
Quantity of milk in container A is 200 × 12/100 = 24
Quantity of water in container A is 24 × 1 /3 = 8
Similarly, we can calculate others containers values.
|
Container |
Quantity of Milk |
Quantity of water |
|
A |
24 |
8 |
|
B |
60 |
24 |
|
C |
56 |
16 |
|
D |
40 |
24 |
|
E |
20 |
5 |
Calculation
Initial in B: Milk = 60, Water = 24
Milk removed = 0.4 × 60 = 24
Water removed = 0.4 × 24 = 9.6
Left in container B:
Milk = 60 – 24 = 36
Water = 24 – 9.6 = 14.4
Add 20L milk
⇒ Milk = 36 + 20 = 56
Water = 14.4
Difference (x) = 56 – 14.4 = 41.6 litres
x = 41.6
Top Pie Chart MCQ Objective Questions
Various expenditures incurred by a publishing company for publishing a book in 2018 are given in the following pie chart. Study the chart and answer the question.
Price printed on a book is 15% above the cost price. If the price printed on a book is Rs. 942, then the cost of paper for a single copy in Rs. is (rounded off to one decimal place)
Answer (Detailed Solution Below)
Pie Chart Question 6 Detailed Solution
Download Solution PDFCalculation:
Let the Cost price of the book be 100
Then, Marked Price of the book is 100 + (15% of 100) = 115
Printed price or marked price = 942
Cost price of book = 942 × (100/115)
⇒ 819.13
Now,
Paper cost = 819.13 × 15/100
⇒ 122.869 ≈ 122.9
∴ The required answer is Rs. 122.9
Study the given pie-chart carefully and answer the following question. If scholarship has to be paid out of the donation fund, then what is the percentage of donation fund used for this purpose (rounded off to two decimal places)?
The entire fund that school gets from different sources is equal to Rs. 10 lakh
Answer (Detailed Solution Below)
Pie Chart Question 7 Detailed Solution
Download Solution PDFCalculation:
Total fund got by school = 100% = 1000000
Funds got through donation = 35%
Scholarship paid = 26%
Required percentage = 26/35 × 100
⇒ 2600/35 = 74.285% ≈ 74.29%
∴ The correct answer is 74.29%.
Directions: Study the following pie chart carefully and answer the questions.
The pie chart given below shows the percentage distribution of the total number of male faculties in six different schools.
Total male faculties in all schools together = 8400
If the total number of faculties in school F is 1820. Then female faculties in school F are what percentage more/less than total male faculties in school B?
Answer (Detailed Solution Below)
Pie Chart Question 8 Detailed Solution
Download Solution PDFGiven:
Total faculties in school F = 1820
Calculation:
It's given that the total number of faculties (Male and Female) in school F is 1820
Female faculties = Total faculties - Male faculties
But according to the chart male percentage in school F = 18%
Total faculties in school F = 1820
Total male faculties in school F = 8400 × 18/100 = 1512
Female faculties in school F = 1820 - 1512 = 308
Male faculties in school B = 8400 × 20/100 = 1680
∴ Required percentage = (1680 - 308)/1680 × 100
⇒ 1372/1680 × 100 = 81.66%.
∴ Female faculties in school F are 81.66% less than male faculties in school B.
Study the given chart and answer the following question.
What is the central angle corresponding to the production steel by Kerala?
Answer (Detailed Solution Below)
Pie Chart Question 9 Detailed Solution
Download Solution PDFCalculation:
Percentage of Kerala in total production =
We know that 100% of the pie chart represents 360°.
Now, the 20% pie chart represents =
∴ The central angle corresponding to the production of steel by Kerala is 72°.
Performance of 1800 students in grades has been shown in the following pie chart.
In which two grades taken together is the number of students 54 less than the number of students in grades B and E taken together?
Answer (Detailed Solution Below)
Pie Chart Question 10 Detailed Solution
Download Solution PDFGiven:
The performance of 1800 students in grades has been shown in the following pie chart.
Calculation:
Total percentage of grades B and E = 27% + 8% = 35%
Here, (54/1800) × 100 = 3%
Then, 54 students of 1800 is 3% students
We have to find the sum of two groups in which the sum of percentage = 35% - 3% = 32%
The percentage of students in Grade C = 24%
The percentage of students in Grade E = 8%
The total percentage of Grade C and E = 24% + 8% = 32%
∴ The number of students is 54 less than the number of students in grades B and E taken together in Grade C and E
The pie chart given below shows the number of truck sold by 8 different companies. The total number of truck sold by all these 8 companies are 4000. Number of truck sold by a particular company is shown as a percent of total number of truck sold by all these 8 companies.
The number of trucks sold by B, C, F and H is how much percent less than the number of trucks sold by all these 8 companies?
Answer (Detailed Solution Below)
Pie Chart Question 11 Detailed Solution
Download Solution PDFCalculation:
Total percentage of trucks sold in B, C, F and H = 27 + 18 + 7 + 14
⇒ 66%
Difference = 100% - 66%
⇒ 34%
∴ The required answer is 34 percent.
The following pie chart represents the percentage distribution of girls in five girls' colleges A, B, C, D and E. The total number of girls in all the five colleges is 2,500.
What is the average number of girls in the colleges C and E?
Answer (Detailed Solution Below)
Pie Chart Question 12 Detailed Solution
Download Solution PDFConcept used:
The sum of variables/No. of variables = Average of variables
Calculation
The number of girls in the colleges C = 20% of 2500
⇒ 500
The number of girls in the colleges E = 26% of 2500
⇒ 650
The average number of girls in colleges C and E = (500 + 650)/2
⇒ 575
The average number of girls in colleges C and E is 575.
The given pie charts show the number of start-ups in various industries since 2010 and the number of successful start-ups in those industries.
Study the charts and answer the question that follows.
Start-ups in various industries started since 2010
Successful start-ups in various industries
What should be the increase in the number (to the nearest integer) of successful start-ups in the industry of Health & sports, so that its success percentage is the same as that of Education?
Answer (Detailed Solution Below)
Pie Chart Question 13 Detailed Solution
Download Solution PDFGiven data:
Total startups in Education = 1280
Successful startup in Education = 520
Total startups in Health and sports = 1050
Successful startup in Health and sports = 300
Calculation:
Successful startup % in education =
Requisite successful startups in Health and sports =
Total increase in the successful startups required for health and sports = 427 - 300 = 127
∴ The answer is 127.
Comprehension:
Direction∶ The given pie chart depicts the expenditure incurred in crores towards each sport.
In the given pie-chart, what will be the central angle of the sector representing football?
Answer (Detailed Solution Below)
Pie Chart Question 14 Detailed Solution
Download Solution PDFTotal expenditure of all sports = 16 + 128 + 72 + 23 + 51 + 10 = 300 crores
Expenditure on football = 51 crores
300 crores represents = 360°
1 crore represents = 360/300°
51 crores will represent = 1.2 × 51 = 61.2°
The pie chart given below shows the number of trucks manufactured by Six companies in a year. Total trucks manufactured by all these Six companies are 2160. Number of trucks manufactured by a particular company is shown in terms of degree with respect to the total number of trucks manufactured by all these Six companies.
Total number of trucks manufactured by L, N and Q is how much percent more than the total number of trucks manufacture by M and R?
Answer (Detailed Solution Below)
Pie Chart Question 15 Detailed Solution
Download Solution PDFCalculation:
Total number of trucks manufactured by L, N and Q = 180° + 72° + 15° = 267°
Total number of trucks manufacture by M and R = 36° + 33° = 69°
Percent more = (267 - 69)/69 × 100 = 286.95%
Therefore total number of trucks manufactured by L, N and Q is how much percent more than the total number of trucks manufacture by M and R is 286.95%.