Question
Download Solution PDFWhat is the value of 64x3 + 38x2y + 20xy2 + y3, when x = 3 and y = - 4?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven
64x3 + 38x2y + 20xy2 + y3
x = 3 and y = - 4
Formula used
(a + b)3 = a3 + b3 + 3ab(a + b)
Calculation:
64x3 + 38x2y + 20xy2 + y3 = (4x + y)3 - 10x2y + 8xy2
⇒ (4x + y)3 - 10x2y + 8xy2 = (12 - 4)3 - 10(3)2(- 4) + 8(3)(- 4)2
⇒ 83 + 360 + 384
⇒ 1256
The value is 1256.
Last updated on Jun 13, 2025
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