Question
Download Solution PDFWhat inductance would be needed to store 2kWh of energy in a coil carrying a 100A current?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The energy stored in an inductor is given by:
\(E={1\over 2}LI^2\)
where, E = Energy
L = Inductance
I = Current
Calculation
Given, E = 2kWh = 2 x 3.6 x 106 J
I = 100 A
\(2\times 10^6\times 3.6={1\over 2}L(100)^2\)
L = 1440 H
Last updated on Jul 1, 2025
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