Question
Download Solution PDFThe Mean deviation about Median for the given data.
52, 56, 66, 70, 75, 80, 82 is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula used
Mean Deviation about median= \(∑\rm \frac{|x_{i} - M|}{n}\)
Where,
xi = individual term
M = Median
n = total number of terms
Calculation:
52, 56, 66, 70, 75, 80, 82
Median = 70
⇒ M = 70
⇒ The value of (xi - M) are
⇒ -18, -14, -4, 0, 5, 10, 12
⇒ Mean Deviation = \(\rm \frac{18 + 14 + 4 + 0 + 5 + 10 + 12}{7}\)
∴ The mean deviation about median is 9
Important Points
The mean is the average of a data set.
The median is the middle of the set of numbers.
Mean deviation about mean
\(∑\rm \frac{|x_{i} - x̅|}{n}\) where x̅ = mean
xi = individual term
n = total number of terms
Last updated on Jul 12, 2025
-> The SSC CGL Application Correction Window Link Live till 11th July. Get the corrections done in your SSC CGL Application Form using the Direct Link.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> The RRB Railway Teacher Application Status 2025 has been released on its official website.
-> The OTET Admit Card 2025 has been released on its official website.