The magnitude of the magnetic field produced inside a solenoid with n turns and current flowing is proportional to ________.

Key Points

• The magnetic field inside a solenoid is given by the formula B = μâ‚€ * n * I, where B is the magnetic field, μâ‚€ is the permeability of free space, n is the number of turns per unit length, and I is the current.
• Since the magnetic field B is directly proportional to the number of turns per unit length (n) and the current (I), it can be concluded that the magnetic field is proportional to nl.
• Thus, the magnitude of the magnetic field produced inside a solenoid is proportional to nl.

Additional Information

• A solenoid is a coil of wire that is used to create a magnetic field when an electric current passes through it.
• The strength of the magnetic field inside a solenoid is uniform and parallel to the axis of the solenoid.
• The magnetic field outside the solenoid is weak and spreads out in all directions.
• The solenoid can be used in various applications such as electromagnets, inductors, and transformers.
• The direction of the magnetic field can be determined using the right-hand rule.