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The following program is stored in the memory unit of the basic computer. Give the content of accumulator register in hexadecimal after the execution of the program.

Location

Instruction

010

CLA

011

ADD 016

012

BUN 014

013

HLT

014

AND 017

015

BUN 013

016

C1A5

017

93C6

 

This question was previously asked in
UGC NET Computer Science (Paper 2) Dec 2019 Paper
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  1. A1B4
  2. 81B4
  3. A184
  4. 8184

Answer (Detailed Solution Below)

Option 4 : 8184
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Detailed Solution

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Location

Instruction

Operation

Content of accumulator

order of instruction

010

CLA

Clear Accumulator

0000

1st

011

ADD 016

ADD (C1A5) to Accumulator

C1A5

2nd

012

BUN 014

Goto address 014

C1A5

3rd

013

HLT

Terminate program

8184

5th

014

AND 017

AND (93C6) with Accumulator

8184

4th

015

BUN 013

Goto address 013

 

 

016

C1A5

 

 

 

017

93C6

 

 

 

 

     C1A5 =1100 0001 1010 0101

& 93C6 = 1001 0011 1100 0110

____________________________

      8184 = 1000 0001 1000 0100

The content of accumulator register in hexadecimal after the execution of the program is 8184

Important Point:

In instruction address in mentioned not data

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