दिलेले समीकरण योग्य करण्यासाठी कोणत्या दोन चिन्हांची अदलाबदल करावी?

81 × 9 + 15 ÷ 3 – 4 = 50

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SSC CGL 2022 Tier-I Official Paper (Held On : 09 Dec 2022 Shift 4)
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  1. − आणि ×
  2. + आणि −
  3. ÷ आणि −
  4. ÷ आणि *

Answer (Detailed Solution Below)

Option 4 : ÷ आणि *
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Detailed Solution

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येथे खालील नमुना खालीलप्रमाणे आहे:

दिलेले समीकरण बरोबर करण्यासाठी कोणती दोन चिन्हे अदलाबदल करावीत ते शोधा.

चला प्रत्येक पर्याय एक एक करून तपासूया.

पर्याय 1) आणि ×

दिलेल्याप्रमाणे: 81 × 9 + 15 ÷ 3 – 4 = 50

चिन्हे अदलाबदल केल्यानंतर आपल्याला मिळते;

⇒ 81 - 9 + 15 ÷ 3 × 4 = 50

⇒ 81 - 9 + 3 × 4 = 50

81 - 9 + 12 = 50

93 - 9 = 50

⇒ 84 ≠ 50

⇒ डावी बाजू ≠ उजवी बाजू

पर्याय 2) + आणि

दिलेल्याप्रमाणे: 81 × 9 + 15 ÷ 3 – 4 = 50

चिन्हे अदलाबदल केल्यानंतर आपल्याला मिळते;

⇒ 81 × 9 - 15 ÷ 3 + 4 = 50

81 × 9 - 5 + 4 = 50

729 - 5 + 4 = 50

733 - 5 = 50

⇒ 728 ≠ 50

⇒ डावी बाजू ≠ उजवी बाजू

पर्याय 3) ÷ आणि

दिलेल्याप्रमाणे: 81 × 9 + 15 ÷ 3 – 4 = 50

चिन्हे अदलाबदल केल्यानंतर आपल्याला मिळते;

⇒ 81 × 9 + 15 - 3 ÷ 4 = 50

81 × 9 + 15 - 0.75 = 50

729 + 15 - 0.75 = 50

⇒ 744 - 0.75 = 50

⇒ 743.25 ≠ 50

⇒ डावी बाजू ≠ उजवी बाजू

पर्याय 4) ÷ आणि ×

दिलेल्याप्रमाणे: 81 × 9 + 15 ÷ 3 – 4 = 50

चिन्हे अदलाबदल केल्यानंतर आपल्याला मिळते;

⇒ 81 ÷ 9 + 15 × 3 – 4 = 50

⇒ 9 + 15 × 3 - 4 = 50

9 + 45 - 4 = 50

⇒ 54 - 4 = 50

⇒ 50 = 50

⇒ डावी बाजू  = उजवी बाजू

म्हणून, योग्य उत्तर "पर्याय 4" आहे.

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