Question
Download Solution PDFजर चौरसाची बाजू (2x + 5) सेमी असेल आणि परिमिती 28 सेमी असेल. तर X चे मूल्य काढा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
बाजू = (2x + 5) सेमी
परिमिती = 28 सेमी
वापरलेले सूत्र:
परिमिती = 4 × बाजू
गणना:
बाजू = (2x + 5) सेमी
परिमिती = 4 × बाजू
⇒ 28 = 4 (2x + 5)
⇒ 2x + 5 = 7
⇒ 2x = 2
⇒ x = 1
∴ x चे मूल्य 1 आहे.
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