Question
Download Solution PDFज्या वर्तुळाचे केंद्र O आणि OP = 17 सेमी आणि OT = 8 सेमी आहे अशा वर्तुळावर PT ही स्पर्शिका असल्यास, PT या स्पर्शिकेच्या खंडाची लांबी शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
PT ही वर्तुळाची स्पर्शिका आहे, ज्याचे केंद्र O आहे.
ओपी = 17 सेमी
OT = 8 सेमी
वापरलेले सूत्र:
पायथागोरस प्रमेय: काटकोन त्रिकोणामध्ये, कर्ण समान आहे -
OP2 = OT2 + TP2
गणना:
हे, स्पर्शिका TP ची लांबी समान आहे:
TP2 = OP2 - OT2
TP2 = (17)2 - (8)2
TP2 = 289 - 64
TP2 = 225
TP = √ 225 = 15
∴ स्पर्शिका खंड PT ची लांबी 15 सेमी एवढी आहे.
Last updated on Jul 19, 2025
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