Question
Download Solution PDFΔPQR ∼ ΔBAC ആണെങ്കിൽ, ΔPQR ൽ, PQ = 7 സെമീ, QR = (2x - 1) സെമീ, ΔABC യിൽ, AB = 14 സെമീ, AC = (3x + 1) സെമീ ആണെങ്കിൽ, QR ന്റെ മൂല്യം എന്താണ്?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFനൽകിയിരിക്കുന്നത്:
ΔPQR ∼ ΔBAC,
ΔPQR- ൽ, PQ = 7 സെമീ, QR = (2x - 1) സെമീ
ΔABC- യിൽ, AB = 14 സെമീ, AC = (3x + 1) സെമീ
ഉപയോഗിച്ച ആശയം:
ΔPQR ∼ ΔBACആണെങ്കിൽ (രണ്ട് ത്രികോണങ്ങളും തുല്യമാണ്)
⇒ PQ / BA = QR / AC = PR / BC
കണക്കുകൂട്ടൽ:
∴ PQ / BA = QR / AC
⇒ 7 / 14 = (2x - 1) / (3x + 1)
⇒ ½ = (2x - 1) / (3x + 1)
⇒ 3x + 1 = 4x - 2
⇒ x = 3
∴ QR = (2x - 1) = (6 - 1) = 5 സെമീ
Last updated on Jul 18, 2025
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