Question
Download Solution PDFLet 'n' denote a positive integer. Suppose a function F is defined as
\(f(n)=\left\{\begin{aligned} 0,& & n =1 \\ f\left(\left\lfloor\frac{n}{2}\right\rfloor+1\right), & & n>1 \end{aligned}\right.\)
What is f(25)? and what does this function find?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is \(4,\left\lfloor\log_2n\right\rfloor\)
Key PointsThis function takes a positive integer n and recursively applies the following operation: Divide the number by 2 (taking the integer floor of the result). At n = 1, the function returns 0.
Since log₂(25) equals 4, our result is also 4. So, correct answer is \(4,\left\lfloor\log_2n\right\rfloor\)
Last updated on Jun 11, 2025
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