Inductance has the dimension of

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UPSSSC JE Electrical 2016 Official Paper 2
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  1. Flux / current
  2. Flux / length
  3. (voltage)2 / current
  4. None of these

Answer (Detailed Solution Below)

Option 1 : Flux / current
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Expressions for Self-inductance:

  • The property of a coil that opposes any change in the amount of current flowing through it is called its self-inductance or inductance.


Factors affecting inductance

  • The greater the self-induced voltage, the greater the self-inductance of the coil, and hence larger is the opposition to the changing current.
  • According to Faraday’s laws of electromagnetic induction, induced voltage in a coil depends upon the number of turns (N) and the rate of change of flux (dφ/dt) linking the coil.
     

Hence, the inductance of a coil depends upon these factors:

  • Shape and number of turns.
  • Relative permeability of the material surrounding the coil.
  • The speed with which the magnetic field changes.
     

Consider an iron-cored solenoid of dimensions as shown in Fig.

F1 Nakshtra Ravi 27.07.21 D1

The inductance of the solenoid (L) is given by,

\(L=N\frac{dϕ}{dI}\)

Now, flux (ϕ) = \(\frac{NI}{S}=\frac{NI}{l/a\mu_0 \mu_r}\)

Where, NI is MMF and S is reluctance,

Differentiating ϕ wrt I,

\(\frac{d\phi}{dI}=\frac{Na\mu_0\mu_r}{l}\)

Now, \(L=N\frac{dϕ}{dI}=N\frac{Na\mu_0\mu_r}{l}=\frac{N^2}{S}\)

Now, inductive reactance (XL) = ωL = \(\dfrac{\omega N^2}{S}\)

Conclusion:

From the above concept,

Inductance has the dimension of Flux/current.

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