Question
Download Solution PDFIf the frame buffer has 10-bits per pixel and 8-bits are allocated for each of the R, G and B components then what would be the size of the color lookup table (LUT)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFrame buffer has 10 bits per pixel and 8 bits are allocated for each R, G and B components.
As frame buffer has 10 bits. So, entries in color lookup table = 210
8 bits for each component. Collectively 24 bits for all three components.
It means 24/8 = 3 bytes are for R, G and B component collectively.
Size of color look up table = number of entries in look up table × size of each entry
Size of look up table = 210 × 3 = 3072 = (210 + 211) BytesLast updated on Jun 12, 2025
-> The UGC NET June 2025 exam will be conducted from 25th to 29th June 2025.
-> The UGC-NET exam takes place for 85 subjects, to determine the eligibility for 'Junior Research Fellowship’ and ‘Assistant Professor’ posts, as well as for PhD. admissions.
-> The exam is conducted bi-annually - in June and December cycles.
-> The exam comprises two papers - Paper I and Paper II. Paper I consists of 50 questions and Paper II consists of 100 questions.
-> The candidates who are preparing for the exam can check the UGC NET Previous Year Papers and UGC NET Test Series to boost their preparations.