Comprehension

Comprehension: Questions concern a disk with a sector size of 512 bytes, 2000 tracks per surface, 50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.

If the disk platters rotate at 5400 rpm (revolutions per minute), then approximately what is the maximum rotational delay ?

This question was previously asked in
UGC NET Computer Science (Paper 2) 2020 Official Paper
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  1. 0.011 seconds
  2. 0.11 seconds
  3. 0.0011 seconds
  4. 1.1 seconds

Answer (Detailed Solution Below)

Option 1 : 0.011 seconds
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UGC NET Paper 1: Held on 21st August 2024 Shift 1
16.1 K Users
50 Questions 100 Marks 60 Mins

Detailed Solution

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The correct answer is option 1.

Key Points

if the disk platters rotate at 5400rpm, the time required for one complete rotation, which is the maximum rotational delay,

5400 rotations= 1 minute

one rotation = \(\frac{1}{5400}\) × 60 seconds

maximum rotational delay = 0.011seconds. 

∴ Hence the correct answer is 0.011seconds.

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