If a, b, c are in A.P., then 3a, 3b, 3c are in

  1. A.P
  2. G.P
  3. H.P
  4. None of these

Answer (Detailed Solution Below)

Option 2 : G.P
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Detailed Solution

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a, b, c are in AP

⇒ b - a = c - b ⇒ 2b = a + c---(1)

if a, b, c are in GP then 

⇒ 

By squaring both the sides we get

 ⇒ 2b = a + c -----(2)

From (1) and (2) we get

The sequence  is a GP.

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