Question
Download Solution PDFनीचे दिखाए गए चित्र में, यदि I धारा β की दर से घटती है, तो VP - VQ है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसही उत्तर विकल्प 4):(- L β ) है।
संकल्पना:
किसी प्रेरक के लिए, विभवांतर
ΔV = L \(di\over dt\)
जहाँ
ΔV वोल्टता में अंतर है,
\(di\over dt\) समय के सापेक्ष धारा के परिवर्तन की दर है
L स्व-प्रेरकत्व है
गणना:
दिया गया है,
\(di\over dt\) = - β
VP - VQ = L \(di\over dt\)
= - Lβ V
Last updated on Jun 16, 2025
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