A wooden block of mass m1 kg accelerates at 10 ms-2 when a force of 5 N acts on it. Another block of mass m2 kg accelerates at 20 ms-2 when the same force acts on it. If both the blocks are tied together and the same force acts on their combination, the acceleration will be about:

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RRB ALP Previous Paper 19 (Held On: 30 Aug 2018 Shift 1)
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  1. 6.67 ms-2
  2. 1.67 ms-2
  3. 5.67 ms-2
  4. 4.67 ms-2

Answer (Detailed Solution Below)

Option 1 : 6.67 ms-2
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Detailed Solution

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CONCEPT:

  • Force: The interaction which after applying on a body changes or try to change the state of motion or state of rest is called force.
  • Force is denoted by F and the SI unit is Newton (N).

Force (F) = Mass (m) × acceleration (a)

Calculation:

Given that,

acceleration of mass m1 = 10m/s2

Force on block m1 = 5 N

acceleration of mass m2 = 20m/s2

As Force = Mass × Acceleration

→ In 1st case according to F = m × a

5 = m1 × 10

m1 = ½

→ In 2nd case according to F = m × a

5 = m2 × 20 [same force is acting in both cases, given in ques]

m2 = ¼

→ now, as the two boxes are tied together the total mass will become

M = m1 + m2

= ½ + ¼ => ¾

→ According to F = M × a

5 = ¾ × a

a = (5 × 4)/ 3 => 20/3

a = 6.67 ms-2 

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