Evaluate using Integration by Parts MCQ Quiz in தமிழ் - Objective Question with Answer for Evaluate using Integration by Parts - இலவச PDF ஐப் பதிவிறக்கவும்

Last updated on Apr 8, 2025

பெறு Evaluate using Integration by Parts பதில்கள் மற்றும் விரிவான தீர்வுகளுடன் கூடிய பல தேர்வு கேள்விகள் (MCQ வினாடிவினா). இவற்றை இலவசமாகப் பதிவிறக்கவும் Evaluate using Integration by Parts MCQ வினாடி வினா Pdf மற்றும் வங்கி, SSC, ரயில்வே, UPSC, மாநில PSC போன்ற உங்களின் வரவிருக்கும் தேர்வுகளுக்குத் தயாராகுங்கள்.

Latest Evaluate using Integration by Parts MCQ Objective Questions

Top Evaluate using Integration by Parts MCQ Objective Questions

Evaluate using Integration by Parts Question 1:

Answer (Detailed Solution Below)

Option 2 :

Evaluate using Integration by Parts Question 1 Detailed Solution

Evaluate using Integration by Parts Question 2:

What is the value of ?

  1. e2 - 1
  2. 2(e - 1)
  3. More than one of the above
  4. None of the above

Answer (Detailed Solution Below)

Option 1 :

Evaluate using Integration by Parts Question 2 Detailed Solution

Calculation:

Given that,

 dx

Putting x2 = t

differentiating w.r.t "t" we get,

⇒ 2x dx = dt ⇒ x dx = 

x = 0, t = 0, x = 1, t = 1

Now, 

The correct answer is option "1'

Evaluate using Integration by Parts Question 3:

Answer (Detailed Solution Below)

Option 4 :

Evaluate using Integration by Parts Question 3 Detailed Solution

Explanation:

Concept: Integration by part

If f and g are two functions, then ∫fg = f∫g - ∫{f'∫g}

If ∫ f(x)dx = F(x), then f(x) = F(b)-F(a)

Let 

We have f = x3 and g = sinx

∴ 

⇒ 

On applying limits of integration,

∴ I = (3(π /2)- 6)
⇒ 

Evaluate using Integration by Parts Question 4:

Let , where n ∈ N. If (20)I10 = αI9 + βI8, for natural numbers α and β, then α - β equals to _________.

Answer (Detailed Solution Below) 1

Evaluate using Integration by Parts Question 4 Detailed Solution

Concept:

Integration By Parts of Definite Integrals formula: 

Calculation:

Given:

Here, u= , v = 

So apply by Parts:

 --------(Since u' = )

 -------( Since )

Put the limits we get,

Now,

 ---(1)

 ----(2)

Subtract (1) from (2)

(20)I10 = 10I9 + 9I8

Comparing with (20)I10 = αI9 + βI8

we get

α = 10 and β = 9

So  α - β = 1

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