Rectangular Waveguide MCQ Quiz - Objective Question with Answer for Rectangular Waveguide - Download Free PDF
Last updated on Jun 12, 2025
Latest Rectangular Waveguide MCQ Objective Questions
Rectangular Waveguide Question 1:
The cut off frequency of TEM wave is
Answer (Detailed Solution Below)
Rectangular Waveguide Question 1 Detailed Solution
Cut-off Frequency of TEM Wave
Definition: The cut-off frequency of a wave refers to the minimum frequency below which the propagation of a particular wave mode ceases in a specific medium or waveguide. For a Transverse Electromagnetic (TEM) wave, the cut-off frequency is a critical parameter that determines the conditions under which the wave can propagate through a waveguide or transmission line.
Correct Option Analysis:
The correct answer is Option 2: DC. This implies that the cut-off frequency for a TEM wave is zero, meaning that TEM waves can propagate even at very low frequencies (including DC). This unique property arises due to the nature of TEM waves, where both the electric and magnetic fields are perpendicular to each other and to the direction of wave propagation.
Why is the Cut-off Frequency for TEM Waves Zero?
- Structure of TEM Waves: TEM waves consist of electric and magnetic fields that are transverse to the direction of propagation. Unlike other wave modes (such as TE or TM modes), TEM waves do not have any longitudinal field components.
- Propagation Conditions: TEM waves do not require a minimum frequency to propagate. As a result, they can exist even at a frequency of zero, which corresponds to DC (Direct Current).
- Waveguide Design: In structures such as coaxial cables or two-wire transmission lines, the geometry allows TEM waves to propagate without requiring a specific minimum frequency.
Applications of TEM Waves:
- Used in coaxial cables for transmitting signals over a wide range of frequencies, including DC.
- Ideal for low-frequency applications due to their zero cut-off frequency.
- Widely used in RF and microwave engineering for signal transmission.
Conclusion:
The zero cut-off frequency of TEM waves makes them highly versatile and suitable for applications across a broad spectrum of frequencies, including DC. This property distinguishes TEM waves from other modes, such as TE and TM modes, which have non-zero cut-off frequencies.
Rectangular Waveguide Question 2:
Which of the following is True for signal travelling through a Wave-Guide?
Answer (Detailed Solution Below)
Rectangular Waveguide Question 2 Detailed Solution
Explanation:
Waveguide and Guide Wavelength
A waveguide is a physical structure that guides electromagnetic waves from one point to another. It is commonly used for high-frequency signal transmission, such as microwave and RF (radio frequency) signals.
The guide wavelength refers to the wavelength of the signal within the waveguide, which differs from the wavelength in free space due to the boundary conditions imposed by the waveguide structure.
Guide Wavelength Formula:
The relationship between the guide wavelength (λg), the free space wavelength (λ0), and the cutoff wavelength (λc) is given by the formula:
λg = λ0 / √(1 - (λ0 / λc)²)
Where:
- λg: Guide wavelength
- λ0: Free space wavelength (c/f, where c is the speed of light and f is the frequency)
- λc: Cutoff wavelength of the waveguide, determined by its dimensions and the operating mode
From this equation, it is evident that λg is always longer than λ0 when the operating frequency is above the cutoff frequency (ensuring wave propagation).
The correct option is: Option 1: Guide wavelength is longer than free space wavelength.
Rectangular Waveguide Question 3:
A rectangular waveguide has dimensions 1 cm × 0.5 cm. Its cut off frequency is :
Answer (Detailed Solution Below)
Rectangular Waveguide Question 3 Detailed Solution
Concept:
The cut-off frequency of a rectangular waveguide in dominant TE10 mode is given by:
c = speed of light =
Calculation:
Given:
Dimensions of waveguide = 1 cm × 0.5 cm
So, a = 1 cm = 0.01 m
Using the formula,
Correct Answer: 2) 15 GHz
Rectangular Waveguide Question 4:
A transmission line has a characteristic impedance of 50 Ω and a resistance of 0.1 Ω /m. If the line is distortionless, the attenuation constant is
Answer (Detailed Solution Below)
Rectangular Waveguide Question 4 Detailed Solution
Concept:
For distortionless transmission line, we have
Characteristic impedance:
Attenuation constant:
Calculation:
From equation (1) and (2), we get
Putting the values of R and Z0, we get
Rectangular Waveguide Question 5:
If in a rectangular waveguide for which a = 2b, the cut-off frequency for TE02 mode is 12 GHz, the cut-off frequency for TM11 mode is -
Answer (Detailed Solution Below)
Rectangular Waveguide Question 5 Detailed Solution
Concept:
Cutt off frequency of TEmn / TMmn mode
Where;
c → Speed of light
a,b → Dimensions of walls
Calculation:
GIven;
a = 2b
Cut off frequency for TE02 mode
fC02 = 12 Ghz
a = 2 × 2.5 = 5 cm
Cut off frequency for TM11 mode
Top Rectangular Waveguide MCQ Objective Questions
The dominant mode in rectangular waveguide is
Answer (Detailed Solution Below)
Rectangular Waveguide Question 6 Detailed Solution
Download Solution PDFConcept:
The dominant mode in a particular waveguide is the mode having the lowest cut-off frequency.
The cut-off frequency for a rectangular waveguide with dimension ‘a (length)’ and ‘b (width)’ is given as:
'm' and 'n' represents the possible modes.
Application:
For a standard rectangular waveguide a > b;
The minimum frequency is obtained when m = 1 and n = 0,
- For a rectangular waveguide with b > a, TE01 will be the dominant mode with the lowest cut-off frequency.
- TEM mode cannot exist in Hollow conductor waveguide
- Circular and rectangular are hollow waveguides hence there is no TEM mode in them, they can support only TE or TM but not TEM mode
- The transmission line, parallel plate waveguide, coaxial cable can have TEM mode
The waveguide can be considered as
Answer (Detailed Solution Below)
Rectangular Waveguide Question 7 Detailed Solution
Download Solution PDFWaveguides only allow frequencies above cut-off frequency and do not pass below the cut-off frequencies.
Hence it acts as a high pass filter.
The cut off frequency is given as:
Where a and b are the dimensions of the waveguide (a>b)
m and n are mode numbers TEmn
In a dispersive medium, the group velocity is:
Answer (Detailed Solution Below)
Rectangular Waveguide Question 8 Detailed Solution
Download Solution PDFIn a dispersive medium, the group velocity is less than the phase velocity only.
Derivation:
Phase velocity is defined as:
β is the phase constant defined as:
Using
Also
Using
Since -1 ≤ cos θ ≤ 1
∴ Vp > c
Group velocity is given by:
Vg = c cos θ
Vg
Conclusion:
The phase velocity is always greater than the speed of light and group velocity is always less than the speed of light. Hence, the group velocity is less than the phase velocity
Extra Information:
For a Non-dispersive medium:
A one-dimensional wave defined as:
U(x, t) = A0 sin (ωt – kx + ϕ) has a phase angle (θ) of ωt – kx + ϕ
In general, the phase is constant,
i.e.
Group velocity is defined as:
Dispersion is when the distinct phase velocities of the components of the envelope cause the wave packet to “Spread out” over time.
When there is no dispersion derivative term is 0 and
Vp = Vg
The wavelength of a wave in a waveguide is
Answer (Detailed Solution Below)
Rectangular Waveguide Question 9 Detailed Solution
Download Solution PDFThe wavelength in a waveguide is considered as a wavelength in the direction of wave propagation and its dependence on wave frequency is defined as follows:
Where λ0 is a wavelength in free space at a given frequency and λc stands for the cutoff wavelength for given waveguide dimensions and waveguide mode.
The wavelength of a wave in a waveguide is greater than in free space. The phase velocity is greater than the speed of light.
Which of the following statements are true?
Answer (Detailed Solution Below)
Rectangular Waveguide Question 10 Detailed Solution
Download Solution PDFConcept:
- The dominant mode in a particular waveguide is the mode having the lowest cut-off frequency.
- Since the frequency and wavelength have an inverse relationship given as:
The cut-off frequency for a rectangular waveguide with dimension ‘a (length)’ and ‘b (width)’ is given as:
'm' and 'n' represents the possible modes.
- For a rectangular waveguide with b > a, TE01 will be the dominant mode with the lowest cut-off frequency.
- TEM mode cannot exist in Hollow conductor waveguide
- Circular and rectangular are hollow waveguides hence there is no TEM mode in them, they can support only TE or TM but not TEM mode
- The transmission line, parallel plate waveguide, coaxial cable can have TEM mode
Degenerate mode in rectangular waveguides is:
Answer (Detailed Solution Below)
Rectangular Waveguide Question 11 Detailed Solution
Download Solution PDFConcept:
Degenerate modes
Whenever the two or more modes having the same cut-off frequency, they are said to be degenerate modes.
For a rectangular waveguide, the cutoff frequency is defined as:
m, n: Mode of operation
a, b: Dimensions of the waveguide
In a rectangular waveguide, TEmn and TMmn modes are always degenerate.
The above cutoff frequency is the same for both TE and TM waves.
For TE waves, Ez = 0 and TM waves have Hz = 0.
The cut-off frequency of TEM wave is
Answer (Detailed Solution Below)
Rectangular Waveguide Question 12 Detailed Solution
Download Solution PDFConcept:
- All electromagnetic waves consist of electric and magnetic fields propagating in the same direction of travel, but perpendicular to each other.
- Along the length of a normal transmission line, both electric and magnetic fields are perpendicular (transverse) to the direction of wave travel. This is known as the principal mode, or TEM (Transverse Electric and Magnetic) mode.
- This mode of wave propagation can exist only where there are two conductors, and it is the dominant mode of wave propagation where the cross-sectional dimensions of the transmission line are small compared to the wavelength of the signal.
- The cutoff frequency of TEM wave is zero.
Microwave energies propagate the length of the waveguide by ____ its sidewalls.
Answer (Detailed Solution Below)
Rectangular Waveguide Question 13 Detailed Solution
Download Solution PDFA rectangular waveguide is a hollow metal tube with a rectangular cross-section.
The conducting walls of the waveguide confine the electromagnetic fields and thereby guide the electromagnetic wave.
Microwave energies propagate the length of the waveguide by the reflection of its sidewalls.
What is the value of the major cross-sectional dimension(width) of a rectangular waveguide with dominant TE10 mode propagation, if its cut off frequency is 10 GHz?
Answer (Detailed Solution Below)
Rectangular Waveguide Question 14 Detailed Solution
Download Solution PDFConcept:
The dominant mode in a particular waveguide is the mode having the lowest cut-off frequency.
The cut-off frequency for a rectangular waveguide with dimension ‘a (length)’ and ‘b (width)’ is given as:
'm' and 'n' represents the possible modes.
c = speed of light = 3 × 1010 cm/s
Calculation:
TE10 mode means m = 1, n = 0
The cut - off frequency of the dominant mode TE10 of the rectangular waveguide is:
Where a is the dimension of the inner broad wall
= 15 mm
________ of a wave is the velocity with which variations in the shape of modulation or envelope of the wave propagate through space.
Answer (Detailed Solution Below)
Rectangular Waveguide Question 15 Detailed Solution
Download Solution PDFGroup Velocity:
The group velocity of a wave is the velocity with which the overall envelope shape of the wave's amplitudes propagates through space.
Group velocity,
Important Points
Phase Velocity:
The phase velocity of a wave is the rate at which the phase of the wave propagates in space.
Phase velocity