Electric Field in Material MCQ Quiz - Objective Question with Answer for Electric Field in Material - Download Free PDF
Last updated on Jun 26, 2025
Latest Electric Field in Material MCQ Objective Questions
Electric Field in Material Question 1:
Which of the following is one of the boundary conditions for time varying fields?
Answer (Detailed Solution Below)
Electric Field in Material Question 1 Detailed Solution
Explanation:
Boundary Conditions for Time-Varying Fields
Definition: Boundary conditions in electromagnetics describe how electromagnetic field quantities behave at the interface between two different media. For time-varying fields, these boundary conditions are derived from Maxwell's equations and are essential for solving electromagnetic problems involving interfaces.
Correct Option:
The correct option is:
Option 3: The normal component of magnetic flux density is continuous at the boundary.
Explanation of Correct Option:
The boundary condition on the magnetic flux density (B) arises from Gauss's law for magnetism, which states:
∇ • B = 0
This implies that the net magnetic flux through any closed surface is zero, meaning magnetic monopoles do not exist. At the boundary between two media, the integral form of Gauss's law for magnetism can be expressed as:
∮ B • dA = 0
When applied to a small Gaussian pillbox that straddles the boundary, the contributions to the flux integral come from the two faces of the pillbox (one in medium 1 and the other in medium 2). The result is:
B₁ₙ = B₂ₙ
Here, B₁ₙ and B₂ₙ are the normal components of the magnetic flux density in the two media. This shows that the normal component of B is continuous across the boundary, regardless of the properties of the media. This condition is fundamental and applies to all interfaces, making Option 3 correct.
Important Note: While the magnetic flux density's normal component is continuous, the tangential component of B may be discontinuous if there is a surface current at the boundary.
Additional Information:
The continuity of the normal component of magnetic flux density ensures that there are no magnetic monopoles, aligning with Maxwell's equations' fundamental principles. This boundary condition is vital for solving problems involving magnetic fields in different media, such as in transformers, inductors, and waveguides.
Analysis of Other Options
To ensure a comprehensive understanding, let’s evaluate the other options:
Option 1: The tangential component of magnetic field intensity is discontinuous across the surface except for a perfect conductor.
This statement is incorrect. The tangential component of the magnetic field intensity (H) is continuous across the boundary unless there is a surface current density (K) present. If a surface current exists, the tangential components of H in the two media are related by:
(H₂ - H₁)ₜ = K
For a perfect conductor, the tangential component of H at the surface is zero, but this condition applies only to perfect conductors, not general boundaries. Thus, Option 1 is not universally correct.
Option 2: The normal component of electric flux density is discontinuous at the boundary if the surface charge density is zero.
This statement is incorrect. The boundary condition for the normal component of the electric flux density (D) is given by:
D₂ₙ - D₁ₙ = ρₛ
Here, ρₛ is the surface charge density at the boundary. If ρₛ is zero, the normal component of D is continuous across the boundary. The statement in Option 2 contradicts this condition by asserting discontinuity even when the surface charge density is zero.
Option 4: The tangential component of electric field intensity is discontinuous at the surface.
This statement is incorrect. The tangential component of the electric field intensity (E) is continuous across the boundary unless there is a time-varying magnetic field present. The boundary condition for the tangential component of E is derived from Faraday's law:
∇ × E = -∂B/∂t
In the absence of time-varying magnetic fields, the tangential component of E is continuous. However, in the presence of time-varying magnetic fields, the tangential component may vary, but this is a specific case and not a general rule. Thus, Option 4 is not universally correct.
Conclusion:
The correct boundary condition for time-varying fields, as described, is that the normal component of magnetic flux density (B) is continuous at the boundary, making Option 3 correct. This condition is derived from Gauss's law for magnetism and is fundamental to the behavior of magnetic fields in different media. The analysis of other options highlights common misconceptions and emphasizes the importance of understanding Maxwell's equations and their implications for boundary conditions.
Electric Field in Material Question 2:
Two large vertical and parallel metal plates having a separation of 1 cm are connected to a DC voltage source of potential difference X. A proton is released at rest midway between the two plates. It is found to move at 45° to the vertical just after release. Then X is nearly
Answer (Detailed Solution Below)
Electric Field in Material Question 2 Detailed Solution
Calculation:
The electric field in the region between the two plates is given by E = X / d.
The proton moves at 45° to the vertical if the net acceleration is along that direction. This happens when the electric force qE equals the gravitational force mg.
So, q(X/d) = mg
⇒ X = (mgd) / q
⇒ X = (1.67 × 10⁻²⁷ kg × 9.8 m/s² × 1 × 10⁻² m) / (1.6 × 10⁻¹⁹ C)
⇒ X ≈ 10⁻⁹ V
Answer: (C) 10⁻⁹ V
Electric Field in Material Question 3:
A potential difference of 3 V is applied across a conductor of resistance 1.5 Ω. The number of electrons flowing through it in one second would be:
(Given charge of an electron: e = 1.6 × 1019 C)
Answer (Detailed Solution Below)
Electric Field in Material Question 3 Detailed Solution
Ans. (3) Sol.
Given:
V = 3 volts
R = 1.5 Ω
e = 1.6 × 10⁻¹⁹ C
t = 1 s
Now, Current I = V / R = 3 / 1.5 = 2 A
Also, I = Q / t = (n × e) / t
So, n = (I × t) / e = (2 × 1) / (1.6 × 10⁻¹⁹) = 1.25 × 10¹⁹
Electric Field in Material Question 4:
A polythene piece rubbed with wool is found to have a negative charge of 3.52 × 10-7 C. What is the number of electrons transferred?
Answer (Detailed Solution Below)
Electric Field in Material Question 4 Detailed Solution
Concept:
The number of electrons transferred when a charge is rubbed or moved can be calculated using the formula:
Q = n × e
Where:
- Q = total charge transferred
- n = number of electrons transferred
- e = elementary charge = 1.6 × 10-19 C
Rearranging the formula to find the number of electrons:
n = Q / e
Calculation:
Given:
- Q = 3.52 × 10-7 C
- e = 1.6 × 10-19 C
n = (3.52 × 10-7) / (1.6 × 10-19) = 2.2 × 1012 electrons
∴ The number of electrons transferred is 2.2 × 1012.
Electric Field in Material Question 5:
At the boundary between two dielectric materials, which of the following is continuous?
Answer (Detailed Solution Below)
Electric Field in Material Question 5 Detailed Solution
- Electric Displacement Field (D): The normal component of the electric displacement field (D) is continuous across the boundary between two dielectrics if there are no free charges at the interface. If there are free charges, the difference in the normal components of D is equal to the surface charge density.
- Electric Field (E): The tangential component of the electric field (E) is continuous across the boundary. However, the normal component of E is discontinuous due to the difference in permittivities of the two materials.
- Magnetic Field (H): The tangential component of the magnetic field (H) can be discontinuous at the boundary. The discontinuity is related to the surface current density at the interface. The normal component of B (magnetic flux density) is always continuous.
- Current Density (J): Current density is related to the flow of charge.
While current can flow along an interface, the normal component of J would be related to the flow of charge across the interface. If there's no accumulation of charge at the boundary, the normal component of J would be continuous. However, the question asks specifically about J, and it is not generally continuous.
Top Electric Field in Material MCQ Objective Questions
Simens is the S.I unit of ________ .
Answer (Detailed Solution Below)
Electric Field in Material Question 6 Detailed Solution
Download Solution PDFOption 2 is correct, i.e. Conductance.
Conductance:
- The degree to which an object conducts electricity, calculated as the ratio of the current which flows to the potential difference present.
- This is the reciprocal of the resistance and is measured in siemens or mhos.
Note:
Conductivity:
- Electrical conductivity is the measure of the amount of electrical current a material can carry or its ability to carry a current.
- It is also known as specific conductance.
- It is an intrinsic property of a material.
- It is denoted by the symbol σ and has SI units of Siemens per meter (S/m).
Resistivity (ρ):
- Resistivity is the resistance per unit length and cross-sectional area.
- It is the property of the material that opposes the flow of charge or the flow of electric current.
- The unit of resistivity is ohm meter.
- A material with high resistivity means it has got high resistance and will resist the flow of electrons.
- A material with low resistivity means it has low resistance and thus the electrons flow smoothly through the material.
- It depends on the material of the conductor but not on its dimensions. ρ is called resistivity.
Resistance:
- It is defined as the hurdles in the path of flow of current.
- The SI unit of resistance is the ohm.
- It is denoted by the symbol Ω.
- It depends on the material of the conductor and the dimensions of the conductor.
- In other words, we can say it is the ratio of voltage to the current.
- R= (rho×length)/area
- Note: rho=Resistivity.
Current carriers in solid conductors are_____.
Answer (Detailed Solution Below)
Electric Field in Material Question 7 Detailed Solution
Download Solution PDFThe correct answer is Free Electrons.
Key Points
- Current carriers in solid conductors are Free Electrons.
- In solid conductors (e.g. metals), there are a large number of free electrons.
- When an electric field (i.e. PD) is applied to the conductor, the free electrons start drifting in a particular direction to constitute that current.
Additional Information
- Some liquids are conductors of electricity.
- A Conducting liquid is called an electrolyte (e.g. solution of CuSO4).
- In conducting liquids, ions (positive and negative) are the current carriers.
- Under ordinary conditions, gases are insulators.
- However, when a gas under low pressure is subjected to a high electric field (i.e. high p.d.), Ionisation of in gases molecules takes place, i.e. electrons and positive ions are formed.
- Hence, current carriers in gases are free electrons and positive ions.
The lightning discharge between clouds during a thunderstorm is 25 C. Find the time of the discharge if the average lightning currect is 2.5 kA.
Answer (Detailed Solution Below)
Electric Field in Material Question 8 Detailed Solution
Download Solution PDFLightning:
The visible discharge of electricity occurs when a region of a cloud acquires an excess electrical charge (either positive or negative) that is sufficient to break down the resistance of air.
Current is a measure of the flow of electric charge over time.
It is defined as
where q = Charge
t = Time
I = Current
Calculation:
Given:
q = 25 C
I = 2.5 kA
t = 10 milliseconds
Two infinite parallel conductors carry currents of '20 A' each. The magnitude of the force between the conductor per metre length if the distance between them is '20 cm' is __________.
Answer (Detailed Solution Below)
Electric Field in Material Question 9 Detailed Solution
Download Solution PDFConcept:
The magnitude of the force between the conductor is given by
Where;
I1,2 → current carried by the conductors
l → Length
d→ Distance between conductors
Calculation:
Given;
I1,2 → current carried by the conductors = 20 A
d→ Distance between conductors = 20 cm = 0.2 m
Then;
The magnitude of the force per meter between the conductor is given by;
Which of the following is the symbol of current density?
Answer (Detailed Solution Below)
Electric Field in Material Question 10 Detailed Solution
Download Solution PDFQuantity | Symbol | Unit |
Current | I | Ampere |
Current Density | J | Amp/m2 |
Magnetic flux | ϕ | Wb |
Flux density | B | Wb/m2 |
Electric field density | D | C/m2 |
Electric field strength | E | V/m |
Magnetic Field Strength | H or I | AT/m |
Charge | Q | C |
Electric flux | Ψ | C |
The magnitude of current density in a superconductor depends on:
Answer (Detailed Solution Below)
Electric Field in Material Question 11 Detailed Solution
Download Solution PDFSuperconductivity: It is the state of the material in which its resistance becomes zero as well as it behaves as perfect diamagnetic when its temperature is reduced below transition temperature Tc and the magnetic field is less than the critical magnetic field Hc.
The current density of the superconductor depends on critical magnetic field strength and temperature.
Superconductors are divided into two types based on magnetic properties:
1) Type-I or Ideal or soft superconductor
2) Type-I or Hard superconductor.
Type-I Superconductor:
A superconducting state is completely diamagnetic up to a certain critical magnetic field (Hc). Above Hc, the superconducting state changes it’s behavior and undergoes to normal state abruptly.
This is explained with the help of the following curve:
Type-II Superconductor:
- It loses their superconductivity gradually because they are made-up by a combination of Hard metal and alloys that show different magnetization behavior.
- It shows superconductivity up to a lower critical magnetic field Hc1 and beyond this, the magnetization changes gradually and reaches zero at upper critical magnetic field Hc2 and due to this, it is useful in the preparation of high-field electromagnets.
Important Points:
Characteristics of superconductors in comparison to a normal metal is as shown:
A conductor carries a current of 8A and if magnitude of charge of an electron e = 1.6 × 10-19 coulomb, then the number of electrons which flow through the cross section per second is -
Answer (Detailed Solution Below)
Electric Field in Material Question 12 Detailed Solution
Download Solution PDFConcept:
Current passing through the conductor, I = q/t = ne / t
Where
n = number of electrons
e = charge of electron
t = time duration
Calculation:
q = e = 1.62 × 10-19
t = 1 sec
⇒ I = n × 1.62 × 10-19
⇒ 8 = n × 1.62 × 10-19
⇒ n = 4.93 × 1019 ≈ 5 × 1019
Consider an interface between two di-electric materials, one with ϵr = 2 while the others have ϵr = 5. If the tangential component of the electric field on one side of the interface has a magnitude of 10 Vm-1. What is the magnitude of the tangential component of the electric field on the other side is?
Answer (Detailed Solution Below)
Electric Field in Material Question 13 Detailed Solution
Download Solution PDFConcept:
The boundary condition for electrostatic fields are defined as:
E1t = E2t (Tangential components are equal across the boundary surface)
Also, the normal component satisfies the following relation:
D1n – D2n = ρs
For a charge-free boundary, ρs = 0, the above expression becomes:
D1n – D2n = 0
D1n = D2n
Calculation:
As Tangential components are equal across the boundary surface
E1t = E2t
E1t = 10 Vm-1
so tangential component of the electric field on the other side is:
E2t = 10 Vm-1
The conduction current density in a conducting medium is given by
Answer (Detailed Solution Below)
Electric Field in Material Question 14 Detailed Solution
Download Solution PDFExplanation
Conduction current density:
- It is defined as the amount of current or charges that flow through the conduction surface within a time 't'.
- The current carried by conductors due to the flow of charges is called conduction current.
- The conduction current follows Ohm's Law
- It is given by: JC = σE
where JC = Conduction current density
σ = Conductivity
E = Electric field
Displacement current density:
- It is defined as the rate of change of the electric displacement field with respect to time 't'.
- The current due to changing electric field is called displacement current.
- The displacement current does not follow Ohm's Law.
- It is given by: JD =
where JD = Displacement current density
Superconductors are becoming popular for their use in
Answer (Detailed Solution Below)
Electric Field in Material Question 15 Detailed Solution
Download Solution PDFSuperconductivity: It is the state of the material in which its resistance becomes zero as well as it behaves as perfect diamagnetic when its temperature is reduced below transition temperature Tc and the magnetic field is less than the critical magnetic field Hc.
Superconductors ripple magnetic field, hence they are creating regions free from magnetic field.
The current density of the superconductor depends on critical magnetic field strength and temperature.
Superconductors are divided into two types based on magnetic properties:
1) Type-I or Ideal or soft superconductor
2) Type-I or Hard superconductor.
Type-I Superconductor:
A superconducting state is completely diamagnetic up to a certain critical magnetic field (Hc). Above Hc, the superconducting state changes it’s behavior and undergoes to normal state abruptly.
This is explained with the help of the following curve:
Type-II Superconductor:
- It loses their superconductivity gradually because they are made-up by a combination of Hard metal and alloys that show different magnetization behavior.
- It shows superconductivity up to a lower critical magnetic field Hc1 and beyond this, the magnetization changes gradually and reaches zero at upper critical magnetic field Hc2 and due to this, it is useful in the preparation of high-field electromagnets.
Important Points:
Characteristics of superconductors in comparison to a normal metal is as shown: