Data Interpretation MCQ Quiz - Objective Question with Answer for Data Interpretation - Download Free PDF
Last updated on Jul 9, 2025
Latest Data Interpretation MCQ Objective Questions
Data Interpretation Question 1:
Comprehension:
Directions: Study the information carefully and answer the questions.
Rajat and Suman jointly acquired a 6-acre fruit orchard in the ratio of 4:2 in the year 2020 and began cultivating apples in the year 2021. In that year, Rajat, being the primary investor, gave 60 kg of apples, which was 10% of his total production for that year, to Suman. As a result, Suman's total apple quantity increased by 30%. In the year 2022, Suman's total apple production was 50% more than the previous year, so he returned 20% of his total apples produced quantity to Rajat. After receiving from Suman, Rajat's total apple quantity increased by 15%. In the year 2023, both had produced an equal quantity of apples, and Rajat's production of apples was increased by 20% over the total quantity of apples he had produced in the previous year.
In which year was the percentage difference between Rajat's and Suman's apple production the greatest?
Answer (Detailed Solution Below)
Data Interpretation Question 1 Detailed Solution
General Solution:
Orchard Area Division
Total land = 6 acres
Rajat : Suman = 4 : 2 ⇒ 2 : 1
Apple Production in 2021:
Let Rajat's production = R₁ kg
He gave 60 kg to Suman, which was 10% of his production
⇒ 10% of R₁ = 60 ⇒ R₁ = 600 kg
Suman got 60 kg which increased his total by 30%
⇒ 60 = 30% of S₁ ⇒ S₁ = 200 kg
2021: Rajat = 600 kg, Suman = 200 kg
2022 Production:
Suman's 2022 production = 50% more than 2021 = 200 + 50% of 200 = 300 kg
He gives 20% of 300 = 60 kg to Rajat
Let Rajat's 2022 own production = R₂
Total apples with Rajat = R₂ + 60 = 15% more than R₂
⇒ R₂ + 60 = R₂ + 15% of R₂ = R₂ × 1.15
⇒ R₂ + 60 = 1.15R₂ ⇒ 60 = 0.15R₂ ⇒ R₂ = 400 kg
2022: Rajat = 400 kg, Suman = 300 kg
2023 Production:
Both produced equal quantities
Rajat's 2023 production is 20% more than previous year = 400 + 20% of 400 = 480 kg
⇒ So, Suman’s 2023 production = 480 kg
2023: Rajat = 480 kg, Suman = 480 kg
Thus:
| Year | Rajat (kg) | Suman (kg) |
|---|---|---|
| 2021 | 600 | 200 |
| 2022 | 400 | 300 |
| 2023 | 480 | 480 |
Calculations:
Calculate percentage difference = |R - S| ÷ ((R + S)/2) × 100
2021: |600 - 200| ÷ 400 × 100 = 400 ÷ 400 × 100 = 100%
2022: |400 - 300| ÷ 350 × 100 ≈ 28.57%
2023: |480 - 480| ÷ 480 × 100 = 0%
Thus, the correct answer is 2021.
Short trick:
The highest difference is in 2021, i.e, 400.
Data Interpretation Question 2:
Comprehension:
Directions: Study the information carefully and answer the questions.
Rajat and Suman jointly acquired a 6-acre fruit orchard in the ratio of 4:2 in the year 2020 and began cultivating apples in the year 2021. In that year, Rajat, being the primary investor, gave 60 kg of apples, which was 10% of his total production for that year, to Suman. As a result, Suman's total apple quantity increased by 30%. In the year 2022, Suman's total apple production was 50% more than the previous year, so he returned 20% of his total apples produced quantity to Rajat. After receiving from Suman, Rajat's total apple quantity increased by 15%. In the year 2023, both had produced an equal quantity of apples, and Rajat's production of apples was increased by 20% over the total quantity of apples he had produced in the previous year.
If the apple price is ₹50 per kg in 2021 and increases by 10% each subsequent year, what is the total revenue earned by Suman over the 3 years (assume that Suman sold his apples after the transactions)?
Answer (Detailed Solution Below)
Data Interpretation Question 2 Detailed Solution
General Solution:
Orchard Area Division
Total land = 6 acres
Rajat : Suman = 4 : 2 ⇒ 2 : 1
Apple Production in 2021:
Let Rajat's production = R₁ kg
He gave 60 kg to Suman, which was 10% of his production
⇒ 10% of R₁ = 60 ⇒ R₁ = 600 kg
Suman got 60 kg which increased his total by 30%
⇒ 60 = 30% of S₁ ⇒ S₁ = 200 kg
2021: Rajat = 600 kg, Suman = 200 kg
2022 Production:
Suman's 2022 production = 50% more than 2021 = 200 + 50% of 200 = 300 kg
He gives 20% of 300 = 60 kg to Rajat
Let Rajat's 2022 own production = R₂
Total apples with Rajat = R₂ + 60 = 15% more than R₂
⇒ R₂ + 60 = R₂ + 15% of R₂ = R₂ × 1.15
⇒ R₂ + 60 = 1.15R₂ ⇒ 60 = 0.15R₂ ⇒ R₂ = 400 kg
2022: Rajat = 400 kg, Suman = 300 kg
2023 Production:
Both produced equal quantities
Rajat's 2023 production is 20% more than previous year = 400 + 20% of 400 = 480 kg
⇒ So, Suman’s 2023 production = 480 kg
2023: Rajat = 480 kg, Suman = 480 kg
Thus:
| Year | Rajat (kg) | Suman (kg) |
|---|---|---|
| 2021 | 600 | 200 |
| 2022 | 400 | 300 |
| 2023 | 480 | 480 |
Calculations:
Apple prices per year:
2021: ₹50 per kg
2022: ₹50 + 10% = ₹55 per kg
2023: ₹55 + 10% = ₹60.5 per kg
Suman's final apple quantity each year
2021: He had 200 kg + 60 kg from Rajat = 260 kg
2022: Produced 300 kg – gave 60 kg to Rajat = 240 kg
2023: Produced = 480 kg
Calculate Revenue for each year:
2021: 260 kg × ₹50 = ₹13,000
2022: 240 kg × ₹55 = ₹13,200
2023: 480 kg × ₹60.5 = ₹29,040
Total Revenue = 13,000 + 13,200 + 29,040 = ₹55,240
Thus, the correct answer is ₹55,240.
Data Interpretation Question 3:
Comprehension:
Directions: Study the information carefully and answer the questions.
Rajat and Suman jointly acquired a 6-acre fruit orchard in the ratio of 4:2 in the year 2020 and began cultivating apples in the year 2021. In that year, Rajat, being the primary investor, gave 60 kg of apples, which was 10% of his total production for that year, to Suman. As a result, Suman's total apple quantity increased by 30%. In the year 2022, Suman's total apple production was 50% more than the previous year, so he returned 20% of his total apples produced quantity to Rajat. After receiving from Suman, Rajat's total apple quantity increased by 15%. In the year 2023, both had produced an equal quantity of apples, and Rajat's production of apples was increased by 20% over the total quantity of apples he had produced in the previous year.
What was the ratio of Rajat's total apples (own production + received) to Suman's total apples (after giving) in 2022?
Answer (Detailed Solution Below)
Data Interpretation Question 3 Detailed Solution
General Solution:
Orchard Area Division
Total land = 6 acres
Rajat : Suman = 4 : 2 ⇒ 2 : 1
Apple Production in 2021:
Let Rajat's production = R₁ kg
He gave 60 kg to Suman, which was 10% of his production
⇒ 10% of R₁ = 60 ⇒ R₁ = 600 kg
Suman got 60 kg which increased his total by 30%
⇒ 60 = 30% of S₁ ⇒ S₁ = 200 kg
2021: Rajat = 600 kg, Suman = 200 kg
2022 Production:
Suman's 2022 production = 50% more than 2021 = 200 + 50% of 200 = 300 kg
He gives 20% of 300 = 60 kg to Rajat
Let Rajat's 2022 own production = R₂
Total apples with Rajat = R₂ + 60 = 15% more than R₂
⇒ R₂ + 60 = R₂ + 15% of R₂ = R₂ × 1.15
⇒ R₂ + 60 = 1.15R₂ ⇒ 60 = 0.15R₂ ⇒ R₂ = 400 kg
2022: Rajat = 400 kg, Suman = 300 kg
2023 Production:
Both produced equal quantities
Rajat's 2023 production is 20% more than previous year = 400 + 20% of 400 = 480 kg
⇒ So, Suman’s 2023 production = 480 kg
2023: Rajat = 480 kg, Suman = 480 kg
Thus:
| Year | Rajat (kg) | Suman (kg) |
|---|---|---|
| 2021 | 600 | 200 |
| 2022 | 400 | 300 |
| 2023 | 480 | 480 |
Calculations:
2022 Apple Quantities:
Rajat's own production in 2022 = 400 kg
He received 60 kg from Suman
Total apples with Rajat = 400 + 60 = 460 kg
Suman's production = 300 kg
He gave 20% of 300 = 60 kg to Rajat
Total apples left with Suman = 300 − 60 = 240 kg
Required Ratio:
⇒ Rajat : Suman = 460 : 240 ⇒ 23 : 12
Thus, the correct answer is 23 : 12.
Data Interpretation Question 4:
Comprehension:
Directions: Study the information carefully and answer the questions.
Rajat and Suman jointly acquired a 6-acre fruit orchard in the ratio of 4:2 in the year 2020 and began cultivating apples in the year 2021. In that year, Rajat, being the primary investor, gave 60 kg of apples, which was 10% of his total production for that year, to Suman. As a result, Suman's total apple quantity increased by 30%. In the year 2022, Suman's total apple production was 50% more than the previous year, so he returned 20% of his total apples produced quantity to Rajat. After receiving from Suman, Rajat's total apple quantity increased by 15%. In the year 2023, both had produced an equal quantity of apples, and Rajat's production of apples was increased by 20% over the total quantity of apples he had produced in the previous year.
If in 2024, both Rajat and Suman decide to increase their production by the average annual percentage increase from 2021 to 2023, what would be the approximate total production in 2024?
Answer (Detailed Solution Below)
Data Interpretation Question 4 Detailed Solution
General Solution:
Orchard Area Division
Total land = 6 acres
Rajat : Suman = 4 : 2 ⇒ 2 : 1
Apple Production in 2021:
Let Rajat's production = R₁ kg
He gave 60 kg to Suman, which was 10% of his production
⇒ 10% of R₁ = 60 ⇒ R₁ = 600 kg
Suman got 60 kg which increased his total by 30%
⇒ 60 = 30% of S₁ ⇒ S₁ = 200 kg
2021: Rajat = 600 kg, Suman = 200 kg
2022 Production:
Suman's 2022 production = 50% more than 2021 = 200 + 50% of 200 = 300 kg
He gives 20% of 300 = 60 kg to Rajat
Let Rajat's 2022 own production = R₂
Total apples with Rajat = R₂ + 60 = 15% more than R₂
⇒ R₂ + 60 = R₂ + 15% of R₂ = R₂ × 1.15
⇒ R₂ + 60 = 1.15R₂ ⇒ 60 = 0.15R₂ ⇒ R₂ = 400 kg
2022: Rajat = 400 kg, Suman = 300 kg
2023 Production:
Both produced equal quantities
Rajat's 2023 production is 20% more than previous year = 400 + 20% of 400 = 480 kg
⇒ So, Suman’s 2023 production = 480 kg
2023: Rajat = 480 kg, Suman = 480 kg
Thus:
| Year | Rajat (kg) | Suman (kg) |
|---|---|---|
| 2021 | 600 | 200 |
| 2022 | 400 | 300 |
| 2023 | 480 | 480 |
Calculations:
2021 total = 600 (Rajat) + 200 (Suman) = 800 kg
2023 total = 480 + 480 = 960 kg
Change over 2 years = 960 − 800 = 160 kg
Average annual % increase = [(Final − Initial)/Initial] ÷ 2 × 100
⇒ (960 − 800)/800 × 100 = 20% over 2 years ⇒ Annual average = 10%
2024 projection = 960 × (1 + 10/100) = 960 × 1.10 = 1056 kg
∴ Approximate total production in 2024 = 1056 kg
Data Interpretation Question 5:
Comprehension:
Directions: Study the information carefully and answer the questions.
Rajat and Suman jointly acquired a 6-acre fruit orchard in the ratio of 4:2 in the year 2020 and began cultivating apples in the year 2021. In that year, Rajat, being the primary investor, gave 60 kg of apples, which was 10% of his total production for that year, to Suman. As a result, Suman's total apple quantity increased by 30%. In the year 2022, Suman's total apple production was 50% more than the previous year, so he returned 20% of his total apples produced quantity to Rajat. After receiving from Suman, Rajat's total apple quantity increased by 15%. In the year 2023, both had produced an equal quantity of apples, and Rajat's production of apples was increased by 20% over the total quantity of apples he had produced in the previous year.
What is the percentage change in the total apples produced by both Rajat and Suman combined in 2022 as compared to 2021?
Answer (Detailed Solution Below)
Data Interpretation Question 5 Detailed Solution
General Solution:
Orchard Area Division
Total land = 6 acres
Rajat : Suman = 4 : 2 ⇒ 2 : 1
Apple Production in 2021:
Let Rajat's production = R₁ kg
He gave 60 kg to Suman, which was 10% of his production
⇒ 10% of R₁ = 60 ⇒ R₁ = 600 kg
Suman got 60 kg which increased his total by 30%
⇒ 60 = 30% of S₁ ⇒ S₁ = 200 kg
2021: Rajat = 600 kg, Suman = 200 kg
2022 Production:
Suman's 2022 production = 50% more than 2021 = 200 + 50% of 200 = 300 kg
He gives 20% of 300 = 60 kg to Rajat
Let Rajat's 2022 own production = R₂
Total apples with Rajat = R₂ + 60 = 15% more than R₂
⇒ R₂ + 60 = R₂ + 15% of R₂ = R₂ × 1.15
⇒ R₂ + 60 = 1.15R₂ ⇒ 60 = 0.15R₂ ⇒ R₂ = 400 kg
2022: Rajat = 400 kg, Suman = 300 kg
2023 Production:
Both produced equal quantities
Rajat's 2023 production is 20% more than previous year = 400 + 20% of 400 = 480 kg
⇒ So, Suman’s 2023 production = 480 kg
2023: Rajat = 480 kg, Suman = 480 kg
Thus:
| Year | Rajat (kg) | Suman (kg) |
|---|---|---|
| 2021 | 600 | 200 |
| 2022 | 400 | 300 |
| 2023 | 480 | 480 |
Calculations:
2021 total = 600 (Rajat) + 200 (Suman) = 800
2022 total = 400 (Rajat) + 300 (Suman) = 700
Change = (700 - 800) ÷ 800 × 100 = -12.5%
Thus, the correct answer is 12.5%.
Top Data Interpretation MCQ Objective Questions
Comprehension:
Given below the data about three employees of a call center named ZINTOCA. In the given table, data about calls received by them, calls selected for further lead and calls finally received is given:
| A | B | C | |
| Initial calls(% out of total calls) | 40% | 30% | 30% |
| Lead calls (% out of initial calls) | 80% | x% | 88% |
| Final received calls(% out of lead calls) | 90% | 80% | y% |
Total number of initial calls in the company is 24000 and total number of calls not received by company C is 4464 less than the total number of calls received by company A. Find the value of y.
Answer (Detailed Solution Below)
Data Interpretation Question 6 Detailed Solution
Download Solution PDFCalculation:
Let the total number of calls be 1000z.
Initial calls (% out of total calls) of A = (1000z × 40/100) = 400z
Initial calls (% out of total calls) of B = (1000z × 30/100) = 300z
Initial calls (% out of total calls) of C = (1000z × 30/100) = 300z
Lead calls (% out of initial calls) of A = (400z × 80/100) = 320z
Lead calls (% out of initial calls) of B = (300z × x/100) = 3zx
Lead calls (% out of initial calls) of C = (300z × 88/100) = 264z
Final received calls (% out of lead calls) of A = (320z × 90/100) = 288z
Final received calls (% out of lead calls) of B = (3zx × 80/100) = 3zx × (4/5)
Final received calls (% out of lead calls) of C = (264z × y/100)
Total number of initial calls in the company = 24000
⇒ (400z + 300z + 300z) = 24000
⇒ 1000z = 24000
⇒ z = (24000/1000)
⇒ z = 24
Total number of calls not received calls by C = (300h – 264z × y/100)
⇒ (300 × 24 – 264z × y/100)
⇒ (7200 – 264z × y/100)
According to the question
Total number of calls not received by company C is 4464 less than the total number of calls received by company A
⇒ (7200 – 264z × y/100) + 4464 = 288z
⇒ (7200 – 264 × 24 × y/100) + 4464 = 288 × 24
⇒ 7200 – 6336y/100 + 4464 = 6912
⇒ (720000 – 6336y + 446400)/100 = 6912
⇒ (720000 – 6336y + 446400) = 6912 × 100
⇒ (1166400 – 6336y) = 691200
⇒ (-6336y) = (691200 – 1166400)
⇒ (-6336y) = -475200
⇒ y = [-475200/(-6336)]
⇒ y = 75
∴ The value of y is 75
The table shows the daily income (in Rs.) of 50 persons.
Study the table and answer the question:
|
Income (Rs) |
No. of persons |
|
Less than 200 |
12 |
|
Less than 250 |
26 |
|
Less than 300 |
34 |
|
Less than 350 |
40 |
|
Less than 400 |
50 |
How many persons earn Rs. 200 or more but less than Rs. 300?
Answer (Detailed Solution Below)
Data Interpretation Question 7 Detailed Solution
Download Solution PDFCalculation:
Number less than 200 = 12
Number less than 250 = 26
Number less than between 250 and 200 = (26 – 12)
⇒ 14
Again,
Number less than 250 = 26
Number less than 300 = 34
Number less than between 300 and 250 = (34 – 26)
⇒ 8
Persons earn Rs. 200 or more but less than Rs. 300 = (14 + 8)
⇒ 22
∴ Required persons is 22
Various expenditures incurred by a publishing company for publishing a book in 2018 are given in the following pie chart. Study the chart and answer the question.
Price printed on a book is 15% above the cost price. If the price printed on a book is Rs. 942, then the cost of paper for a single copy in Rs. is (rounded off to one decimal place)
Answer (Detailed Solution Below)
Data Interpretation Question 8 Detailed Solution
Download Solution PDFCalculation:
Let the Cost price of the book be 100
Then, Marked Price of the book is 100 + (15% of 100) = 115
Printed price or marked price = 942
Cost price of book = 942 × (100/115)
⇒ 819.13
Now,
Paper cost = 819.13 × 15/100
⇒ 122.869 ≈ 122.9
∴ The required answer is Rs. 122.9
Study the given pie-chart carefully and answer the following question. If scholarship has to be paid out of the donation fund, then what is the percentage of donation fund used for this purpose (rounded off to two decimal places)?
The entire fund that school gets from different sources is equal to Rs. 10 lakh
Answer (Detailed Solution Below)
Data Interpretation Question 9 Detailed Solution
Download Solution PDFCalculation:
Total fund got by school = 100% = 1000000
Funds got through donation = 35%
Scholarship paid = 26%
Required percentage = 26/35 × 100
⇒ 2600/35 = 74.285% ≈ 74.29%
∴ The correct answer is 74.29%.
The given data shows the registration of bikes and total vehicles (in thousands) for 6 months in 2017 in City X.
Note: In the chart, the first number represents bikes and the second number represents total vehicles.
Based on the given data, the increase in the registration of vehicles other than bikes in April 2017 in comparison of Jan 2017 is _______.
Answer (Detailed Solution Below)
Data Interpretation Question 10 Detailed Solution
Download Solution PDFNumber of registration of vehicles other than bikes in January 2017 = 27,000 - 21,000 = 6,000
Number of registration of vehicles other than bikes in April 2017 = 35,000 - 20,000 = 15,000
∴ the increase in the registration of vehicles other than bikes in April 2017 in comparison of Jan 2017 = 15,000 - 6,000 = 9,000
Directions: The data for family sizes in a town is given below. Based on the bar graph, answer the question given below:
Calculate the average family size from the given data.
Answer (Detailed Solution Below)
Data Interpretation Question 11 Detailed Solution
Download Solution PDFCalculation:
Number of families having 1 member = 5
Total members = 5
Number of families having 2 members = 30
Total members = 60
Number of families having 3 members = 45
Total members = 135
Number of families having 4 members = 40
Total members = 160
Number of families having 5 members = 25
Total members = 125
Number of families having 6 members = 5
Total members = 30
So, the total membes in all types of families = 5 + 60 + 135 + 160 + 125 + 30 = 515
Total number of families = 5 + 30 + 45 + 40 + 25 + 5 =150
The average family size = 515 / 150 = 3.4
Hence, option 3 is correct.
Study the given table and answer the question that follows.
The table shows the classification of 100 students based on the marks obtained by them in History and Geography in an examination.
|
Subject |
Marks out of 50 |
||||
|
40 and above |
30 and above |
20 and above |
10 and above |
0 and above |
|
|
History |
9 |
32 |
80 |
92 |
100 |
|
Geography |
4 |
21 |
66 |
81 |
100 |
|
Average (Aggregate) |
7 |
27 |
73 |
87 |
100 |
Based on the table, what is the number of students scoring less than 20% marks in aggregate?
Answer (Detailed Solution Below)
Data Interpretation Question 12 Detailed Solution
Download Solution PDFCalculation
We have 20% of 50 = 10
Therefore Required number:
Number of students scoring less than 10 marks in aggregate
= 100 - Number of students scoring 10 and above marks in aggregate
= 100 - 87
= 13.
The number of students scoring less than 20% marks in aggregate is 13.
The line chart given below shows the profit percentage of a company on 5 different products P1, P2, P3, P4 and P5.
The expenditure of product P5 is Rs. 46000. What is the revenue of product P5?
Answer (Detailed Solution Below)
Data Interpretation Question 13 Detailed Solution
Download Solution PDFGIVEN:
From the chart
Profit percentage in P5 = 8%
Expenditure = Rs. 46000
FORMULA USED:
Profit percentage = [(Revenue – Expenditure)/Expenditure] × 100
CALCULATION:
Profit percentage = [(Revenue – Expenditure)/Expenditure] × 100
⇒ 8 = [(Revenue – 46000)/46000] × 100
⇒ Revenue – 46000 = 8 × 460
⇒ Revenue = 3680 + 46000
⇒ Revenue = 49680
The following table shows the number of different items in different shops and their respective selling prices per unit.
|
Shops |
Total No. of Items |
AC ∶ Cooler ∶ Fan |
Selling Price per unit |
||
|
Cooler |
AC |
Fan |
|||
|
A |
5000 |
4 ∶ 5 ∶ 1 |
8000 |
25000 |
8500 |
|
B |
1800 |
3 ∶ 2 ∶ 4 |
10000 |
20000 |
16000 |
|
C |
3400 |
6 ∶ 4 ∶ 7 |
6000 |
42000 |
15000 |
|
D |
3600 |
4 ∶ 2 ∶ 3 |
12000 |
32000 |
8000 |
|
E |
4000 |
5 ∶ 1 ∶ 4 |
8000 |
26500 |
12200 |
|
F |
1210 |
2 ∶ 4 ∶ 5 |
11000 |
28000 |
11100 |
Find the percentage of total revenue which comes from Cooler from shop E, considering all given items are being sold from shop E and from all the given shops only given three items are being sold. (Rounded off to three decimal places)
Answer (Detailed Solution Below)
Data Interpretation Question 14 Detailed Solution
Download Solution PDFCalculation:
Total cooler sold by shop E = 4000 × (1/10)
⇒ 400
Selling price of 400 coolers = 400 × 8000
⇒ 3200000
Total ACs sold by shop E = 4000 × (5/10)
⇒ 2000
Selling price of 2000 ACs = 2000 × 26500
⇒ 53000000
Total Fans sold by shop E = 4000 × (4/10)
⇒ 1600
Selling price of 1600 Fans = 1600 × 12200
⇒ 19520000
Now,
Required % = [3200000/(3200000 + 53000000 + 19520000)] × 100
⇒ [3200000/(75720000)] × 100
⇒ 4.226 ≈ 4.23%
∴ The required answer is 4.23%.
study the given table and answer the question that follows.
The table shows the classification of 100 students based on the marks obtained by them in Statistics and Mathematics in an examination out of 50.
| Subject | 40 and above | 30 and above | 20 and above | 10 and above | 0 and above |
| Mathematics | 8 | 33 | 90 | 92 | 100 |
| Statistics | 5 | 22 | 60 | 87 | 100 |
If at least 60% marks in Mathematics are required for pursuing higher studies in Mathematics, then how many students will be eligible to pursue higher studies in Mathematics?
Answer (Detailed Solution Below)
Data Interpretation Question 15 Detailed Solution
Download Solution PDFCalculation:
Total marks = 50
Eligible for higher studies in mathematics marks = 50 × 60% = 30
Total students who are eligible to pursue higher studies in mathematics = 33
∴ The correct answer is 33.