Question
Download Solution PDFWhat rating of shunt capacitor is needed to improve the power factor of a 400 V, 50 Hz, 240 kW load from 0.8 to unity?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The rating of shunt capacitor is needed to improve the power factor is given by:
where, Q = Reactive Power
P = Active Power
ϕ1 = Power factor angle before power factor improvement
ϕ2 = Power factor angle after power factor improvement
Calculation
Given, P = 240 kW
cos ϕ1 = 0.8 ⇒ ϕ1 = 36.86°
cos ϕ2 = 1 ⇒ ϕ2 = 0°
Q = 180 kVAr
Last updated on May 29, 2025
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