What is the distance of the centre of gravity from any side of an equilateral triangle with side length 'x' ?

Question

Question

This question was previously asked in

PGCIL DT Civil 5 May 2023 Official Paper

Answer 1

Concept:

The centre of gravity of an equilateral triangle will be \( = \frac{1}{3}h\)

Calculation:

SSC JE CE 16 SOM images Q21

\(h^2+ ({\frac a2})^2=a^2\)

\(h= \frac{{\sqrt 3 }}{2}a\)

The centre of gravity of an equilateral triangle will be \( = \frac{1}{3}h\)

\(= \frac{1}{3} \times \frac{{\sqrt 3 }}{2}a = \frac{a}{{2\sqrt 3 }}\)