The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is v_e = . Then

Concept:

According to wave-particle duality, the de-Broglie wavelength in Quantum Mechanics determines the probability density of finding the object in a space

where h is Planck constant and p is momentum.

Momentum is the product of mass and volume and is defined as 

⇒ p = mv

Solution:

λ_e = 

We know Kinetic Energy is given by

K.E=

λ = 

⇒ 

⇒ = 100 = 10⁽²⁾

⇒ 

Again P_e=m_ev_e

⇒ = 10^(-2)

The correct answer is option (2)