Sum to infinity of a geometric is twice the sum of first two terms. Then what are the possible values of the common ratio?

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  1. \(\pm \frac{1}{\sqrt{2}}\)
  2. \(\pm \frac{1}{2}\)
  3. \(\pm \frac{1}{\sqrt{3}}\)
  4. \(\pm \frac{1}{3}\)

Answer (Detailed Solution Below)

Option 1 : \(\pm \frac{1}{\sqrt{2}}\)
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NIMCET 2020 Official Paper
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120 Questions 480 Marks 120 Mins

Detailed Solution

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Concept:

  • Geometric Progression (GP): The series of numbers where the ratio of any two consecutive terms is the same, is called a Geometric Progression.
  • A Geometric Progression of n terms with first term a and common ratio r is represented as:

    a, ar, ar2, ar3, ..., arn-2, arn-1

  • The sum of the first n terms of a GP is: Sn\(\rm a\left(\frac{r^n-1}{r-1}\right)\).
  • If |r| < 1, then S = \(\rm \frac{a}{1-r}\).

 

Calculation:

Let the first term of the GP be a and the common ratio be r.

According to the question:

S = 2(a + ar)

⇒ \(\rm \frac{a}{1-r}=2a(1+r)\)

⇒ \(\rm (1+r)(1-r)=\frac{1}{2}\)

⇒ \(\rm 1-r^2=\frac{1}{2}\)

⇒ \(\rm r^2=\frac{1}{2}\)

⇒ \(\rm r=\pm\frac{1}{\sqrt2}\)

Hence, the possible values of the common ratio are \(\pm \frac{1}{\sqrt{2}}\).

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