Question
Download Solution PDFRaju, Shobh and Mohan can do a work in 15 days, 20 days and 25 days respectively. In how many days,will the work be finished, if they do it on alternate days, Starting from Raju?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Raju, Shobh and Mohan can do a work in 15 days, 20 days and 25 days respectively.
Concept used:
Total work = Efficiency (Work done per day) × Total time taken
Calculation:
Let the total work be 300 units.
Efficiency of A (Raju) = 300/15 = 20 units/day
Efficiency of B (Shobh) = 300/20 = 15 units/day
Efficiency of C (Mohan) = 300/25 = 12 units/day
In three days, working on alternate days, they complete = (20 + 15 + 12) = 47 units of work
In such a manner, total work in 6 such sets of 3 days = 47 × 6 = 282 units
Remaining work = 300 - 282 = 18 units
Time taken to complete 18 units of work by A = \(\frac {18}{20} = \frac {9}{10}\ days\)
Total time taken = 6 × 3 + \(\frac {9}{10}\) = \(18\frac{9}{{10}}\) days
∴ The total time taken to complete the work is \(18\frac{9}{{10}}\) days.
Last updated on Jul 17, 2025
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