दिलेल्या संचाच्या संख्यांप्रमाणेच संबंधित संख्या असलेला संच निवडा.

(सूचना: संख्यांचे घटक अंकांमध्ये खंडित न करता, संपूर्ण संख्यांवर क्रिया केल्या पाहिजेत. उदा. 13 - 13 वर क्रिया जसे की13ची बेरीज/वजाबाकी/गुणाकार करणे इ.करता येते. 13 ला 1 आणि 3 मध्ये वेगळे करणे आणि नंतर 1 आणि 3 वर गणिती क्रिया करण्यास परवानगी नाही.)

(6, 16, 8)

(5, 15, 9)

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SSC CGL 2023 Tier-I Official Paper (Held On: 21 Jul 2023 Shift 1)
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  1. (4, 12, 11)
  2. (3, 11, 11)
  3. (3, 19, 11)
  4. (4, 32, 8)

Answer (Detailed Solution Below)

Option 2 : (3, 11, 11)
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Detailed Solution

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तर्क: [(दुसरी संख्या x 3) ÷ पहिली संख्या] = तिसरी संख्या

दिलेली माहिती:

  • (6, 16, 8)

(16 x 3) ÷ 6 = 8

48 ÷ 6 = 8

8 = 8 (डाव्या हाताची बाजू = उजव्या हाताची बाजू)

  • (5, 15, 9)

(15 x 3) ÷ 5 = 9

45 ÷ 5 = 9

9 = 9 (डाव्या हाताची बाजू = उजव्या हाताची बाजू)

तर,

  • पर्याय - (1): (4, 12, 11)

(12 x 3) ÷ 4 = 11

36 ÷ 4 = 11

9 ≠ 11(डाव्या हाताची बाजू ≠ उजव्या हाताची बाजू)

  • पर्याय - (2): (3, 11, 11)

(11 x 3) ÷ 3 = 11

33 ÷ 3 = 11

11 = 11 (डाव्या हाताची बाजू = उजव्या हाताची बाजू)

  • पर्याय - (3): (3, 19, 11)

(19 x 3) ÷ 3 = 11

57 ÷ 3 = 11

19 ≠ 19 (डाव्या हाताची बाजू ≠ उजव्या हाताची बाजू)

  • पर्याय - (4) : (4, 32, 8)

(32 × 3) ÷ 4 = 8

96 ÷ 4 = 8

24 ≠ 8 (डाव्या हाताची बाजू ≠ उजव्या हाताची बाजू)

म्हणून,"पर्याय - (2)" हे योग्य उत्तर आहे.

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