Question
Download Solution PDFABCD एक समद्विभुज समलंब चौकोन आहे ज्यामध्ये AD ||BC, AB = 5 सेमी, AD = 8 सेमी आणि BC = 14 सेमी. समलंब चौकोनाचे क्षेत्रफळ (cm2 मध्ये) किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFवरील आकृतीवरून AOB त्रिकोणामध्ये पायथागोरस प्रमेय वापरून
⇒ AB2 = BO2 + OA2
⇒ 52 = 32 + OA2
⇒ OA = 4cm जे समलंब चौकोनाच्या उंचीच्या बरोबरीचे आहे.
⇒ क्षेत्रफळ = 1/2 × (उंची) × (समांतर बाजूंची बेरीज)
⇒ क्षेत्रफळ = 1/2 × 4 × (8 + 14) = 44
∴ क्षेत्रफळ 44cm2 आहे
Last updated on Jul 19, 2025
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