Question
Download Solution PDFIn actual air-conditioning applications for R-12 and R-22 refrigerant and operating at a condenser temperature of 40°C and an evaporator temperature of 5°C, the heat rejection factor is about:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Vapour Compression Refrigeration Cycle:
Process 1-2: Isentropic Work Done by Compressor
Process 2-3: Constant Pressure Heat Removal by Condenser
Process 3-4: Isentropic Expansion by Throttling Valve
Process 4-1: Constant Pressure Heat Addition by Evaporator
From the Heat Balance Equation:
Energy transferred from Condenser = Energy Transferred to Evaporator + Work Input to the compressor
Heat rejection ratio is given by:
Or
Where,
QCOND is heat rejected in the condenser,
RE is the Refrigeration effect and Winput is the work input to the Refrigeration System
Calculation:
Given:
TC = 40°C and TE = 5°C
Heat rejection factor =
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