In a Rutherford scattering experiment when a projectile of charge Z1 and mass M1 approaches a target nucleus of charge Z2 and mass M2, the distance of closest approach is r0. The energy of the projectile is 

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  1. directly proportional to Z1Z2
  2. inversely proportional to Z1
  3. directly proportional to mass M1
  4. directly proportional to M1 × M2

Answer (Detailed Solution Below)

Option 1 : directly proportional to Z1Z2
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Concept:

The distance of closest approach (r0) in a Rutherford scattering experiment is inversely proportional to the kinetic energy (K) of the projectile. Mathematically,

r0 = k / K

where k is a constant that depends on the charges of the projectile and the target nucleus.

For a projectile of charge Z1 and a target nucleus of charge Z2, the constant k is given by:

k = (Z1 Z2 e2) / (4 π ε0)

Thus, the energy of the projectile (K) can be written as:

K = (Z1 Z2 e2) / (4 π ε0 r0)

Calculation:

We are given the distance of closest approach r0 and need to determine the relationship between the energy of the projectile and the charges Z1 and Z2.

⇒ K = (Z1 Z2 e2) / (4 π ε0 r0)

From this formula, we can see that the energy K is directly proportional to the product of the charges Z1 and Z2.

∴ The energy of the projectile is directly proportional to Z1Z2.

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