Question
Download Solution PDFIn a non – flow process, work transfer from the system is 30 kJ, and heat received by the system is 90 kJ. Determine the change in the internal energy.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Applying the first law of thermodynamics to the given non-flow system,
Q = Δ U + W
Calculation:
Given:
W = 30 kJ (Positive since work transfer from the system), Q = 90 kJ (Positive since heat transfer to the system)
Now,
Q = ΔU + W
90 = ΔU + 30
∴ ΔU = 60 kJ
Last updated on May 28, 2025
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