निम्न में से कौन सा सत्य कथन है?

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RPSC 2nd Grade Mathematics (Held on 18th Feb 2019) Official Paper
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  1. ∇ × (∇ϕ) = 
  2. ∇ ⋅ (ϕ) = ϕ(∇f) +  ⋅ (∇ϕ)
  3. ∇ ⋅ ( × ) =  ⋅ (∇ × ) −  ⋅ (∇ × )
  4. ∇ × (∇ × ) = ∇(∇ ⋅ ) + ∇2

Answer (Detailed Solution Below)

Option 2 : ∇ ⋅ (ϕ) = ϕ(∇f) +  ⋅ (∇ϕ)
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RPSC Senior Grade II (Paper I): Full Test 1
100 Qs. 200 Marks 120 Mins

Detailed Solution

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दूसरा विकल्प ∇ (ϕ) = ϕ(∇f) +  ⋅ (∇ϕ) सही है।

संकल्पना:

गुणनफल नियम

  • जैसा कि गुणनफल नियम इंगित करता है, आइए दो सरल फलन f और g लेते हैं और दोनों अवकलनीय हैं। 

⇒  

  • अब उसी गुणनफल नियम को सादृश्यता नियम द्वारा दो सदिश फलनों ϕ और  पर लेने पर। 

​⇒ ∇ ⋅ (ϕ) = ϕ(∇f) +  ⋅ (∇ϕ)

प्रमाण:

आइए δ को दो सदिश फलन ϕ और  के गुणनफल के रूप में लेते हैं।

∴ δ = ϕ  ................(1)

अब फलन δ को अवकलित करने पर 

∴ δ' =  

∴ δ' = 

∴ δ' =  ϕ (x + h) ⋅   +   ⋅  

∴ δ' = 

∴ δ' = ϕ(∇f) +  ⋅ (∇ϕ)   .............(2)

समीकरण (1) से ⇒ δ = ϕ

⇒ δ' या δ = ∇ ⋅ (ϕ)   ...............(3)

समीकरणों (2) और (3) से।

∇ ⋅ (ϕ) = ϕ(∇f) +  ⋅ (∇ϕ)

  • अत: यह सत्य है और विकल्प 2 सत्य हो जाता है।

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