Question
Download Solution PDFएक रेखा AB का अक्षांश औऱ विचलन क्रमशः +78 m और -45.1 m है।रेखा AB का पूर्ण वृत्त बेअरिंग क्या होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
एक त्रुटि मुक्त आयोजित अनुप्रस्थ के लिए:
ΣL = 0, ΣD = 0
ΣL = सभी बाजूओं के अक्षांश का बीजगणितीय योग
ΣD = सभी बाजूओं के विचलन का बीजगणितीय योग
खण्ड AB के लिए
अक्षांश = L cos θ & Departure = L sin θ
गणना:
From the figure
∴ θ = - 30°
The whole circle bearing of the line AB is
α = - 30° + 360° = 330°
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