माध्य (M), माध्यिका (Md), और बहुलक (M0) के बीच अनुभवजन्य संबंध है:

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SSC CGL JSO Tier-II, 2018 (Statistics) Official Paper-III (Held On: 14 Sept, 2019)
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  1. M0 = 3Md - 2M
  2. M0 = 2Md - 3M
  3. M0 = 2Md + 3M
  4. M0 = 3Md + 2M

Answer (Detailed Solution Below)

Option 1 : M0 = 3Md - 2M
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गणना:

माध्य (M), माध्यिका (Md), और बहुलक (M0) के बीच अनुभवजन्य संबंध

⇒ M0 = 3Md - 2M

 

माध्य = प्रतिरूप में सभी मानों का कुल योग अवलोकन की संख्या से विभाजित होता है और इसे x̅ द्वारा दर्शाया जाता है

x̅ = ∑fi/n और I = 1, 2, 3, -------

माध्यिका = वितरण की माध्यिका एक केंद्रीय बिंदु को ज्ञात करती है जो वितरणन को दो बराबर भागों में विभाजित करता है। 

माध्यिका = (n + 1)/2

बहुलक = बहुलक वितरण का वह मान है जिसकी आवृत्ति अधिक होती है। 

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