उस समूह का चयन कीजिए जिसमें संख्याएँ उसी तरह संबंधित नहीं हैं जिस तरह कि निम्नलिखित समूह की संख्याएँ हैं।

(4, 11, 137), (3, 12, 153)

(नोट: संख्याओं को उसके घटक अंकों में तोड़े बिना, पूर्ण संख्याओं पर संक्रियाएँ की जानी चाहिए।)

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SSC CGL 2023 Tier-I Official Paper (Held On: 21 Jul 2023 Shift 3)
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  1. (7, 8, 113)
  2. (13, 14, 365)
  3. (9, 11, 202)
  4. (4, 3, 61)

Answer (Detailed Solution Below)

Option 4 : (4, 3, 61)
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दिया गया है:

(4, 11, 137)

(3, 12, 153)

तर्क: तीसरी संख्या = [(पहली संख्या)2 + (दूसरी संख्या)2]

(4, 11, 137) →

⇒ [(4)2 + (11)2]

⇒ (16 + 121) = 137

(3, 12, 153) →

⇒ [(3)2 + (12)2]

⇒ (9 + 144) = 153

दिए गए सभी विकल्पों की जाँच करने पर,

1. (7, 8, 113) →

⇒ [(7)2 + (8)2]

⇒ (49 + 64) = 113

2. (13, 14, 365) →

⇒ [(13)2 + (14)2]

⇒ (169 + 196) = 365

3. (9, 11, 202) →

⇒ [(9)2 + (11)2]

⇒ (81 + 121) = 202  

4. (4, 3, 61) →

⇒ [(4)2 + (3)2]

⇒ (16 + 9) = 25

यहाँ, (4, 3, 61) में भिन्न तर्क का अनुसरण किया गया है।

अतः सही उत्तर "विकल्प (4)" है।

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