एक तुल्यकालिक जनित्र को 40 MVA, 10 kV और 50 Hz पर पाठ्यांकित (रेटेड) किया गया है। इस जनित्र का आधारीय प्रतिघात कितना होगा?

This question was previously asked in
HPCL Engineer Electrical 01 Nov 2022 Official Paper
View all HPCL Engineer Papers >
  1. 10 Ω 
  2. Ω
  3. 7.5 Ω
  4. 2.5 Ω

Answer (Detailed Solution Below)

Option 4 : 2.5 Ω
Free
Environmental Engineering for All AE/JE Civil Exams Mock Test
20 Qs. 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

सही उत्तर विकल्प 4):(2.5 Ω) है।

संकल्पना:

AC जालक्रम के लिए,

VA रेटिंग (दर) = 

जहाँ V वोल्ट में वोल्टता है

Z, Ω में प्रतिबाधा (आधार) है

गणना:

VA रेटिंग (दर= 40 MVA = 40 × 106 VA

V = 10 × 103 volts

Latest HPCL Engineer Updates

Last updated on Jun 2, 2025

-> HPCL Engineer 2025 notification has been released on June 1, 2025.

-> A total of 175 vacancies have been announced for the HPCL Engineer post in Civil, Electrical, Mechanical, Chemical engineering.

-> HPCL Engineer Online application will be activated from 1st June 2025 to 30th June 2025.

-> Candidates with a full-time engineering discipline in the relevant stream are eligible to apply.

-> The selection will be based on a Computer Based Test Group Task and/or Interview. Prepare for the exam using HPCL Engineer Previous Year Papers.

More Per Unit System Questions

More PU System and Symmetrical Components Questions

Hot Links: teen patti online yono teen patti teen patti fun