Question
Download Solution PDFएक 50 Hz 4 ध्रुव एकल फेज मोटर सर्पी 3.4% के साथ चल रही है। मोटर की गति क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFधारणा:
तुल्यकालिक गति को निम्न रूप में दिया जाता है
सर्पी को निम्न रूप में दिया जाता है
Nr = (1 - s) Ns
जहाँ
Nr = rpm में रोटर की गति
f = Hz में आपूर्ति आवृत्ति
P = ध्रुवों की संख्या
गणना:
दिया हुआ-
f = 50 Hz, P = 4,
s = 3.4% = 0.034
अब तुल्यकालिक गति की गणना इसप्रकार की जा सकती है
इसलिए 1 -ϕ मोटर की गति है
Nr = (1 - 0.034) x 1500
Nr = 1449 rpm
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