Find the point at which the line segment joined by the points (- 1, 0) and (2, 6) is divided internally in the ratio 2 : 1.

Question

Question

This question was previously asked in

RRC Group D Previous Paper 5 (Held On: 23 Sep 2018 Shift 1)

Answer 1

⇒ Section formula for internal division = {[(mx₂ + nx₁)/(m + n)], [(my₂ + ny₁)/(m + n)]}

⇒ Here, x₁, y₁ = (- 1, 0) and x₂, y₂ = (2, 6). m : n = 2 : 1

⇒ [(2 × 2) + (1 × - 1)]/(2 + 1), [(2 × 6) + (1 × 0)]/(2 + 1) = (1, 4)

∴ The line segment joined by the points (- 1, 0) and (2, 6) is divided internally in the ratio 2 : 1 at the point (1, 4).