Determine the load resistance RL that will result in maximum power delivered to the load for the given circuit. Also, determine the maximum power Pmax delivered to the load resistor.

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SSC JE EE Previous Paper 12 (Held on: 24 March 2021 Evening)
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  1. RL = 50 Ω; Pmax = 225 W
  2. RL = 35 Ω; Pmax = 200 W
  3. RL = 20 Ω; Pmax = 200 W
  4. RL = 25 Ω; Pmax = 225 W

Answer (Detailed Solution Below)

Option 4 : RL = 25 Ω; Pmax = 225 W
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RRB JE CBT I Full Test - 23
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Detailed Solution

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Concept:

Maximum power transfer for DC circuit:

According to the MPT the maximum power transfer to the load when the load resistance is equal to the source resistance or Thevenin resistance.

RL = Rth 

RL = load resistance

Rth = Thevenin or source resistance

The power at maximum power transfer (Pmax) = Vth2 / 4Rth

The maximum power transfer theorem is used in electrical circuits.

Calculation:

Rth = RL

= ( 30 × 150 )  / 180

= 25 Ω 

Vth = Vab 

= ( 150 × 180 ) / (150 + 30 )

= 150 V

From above concept,

Pmax = 225 W

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