Consider a CIDR network address 194.24.0.0/21. The last address in this network will be:

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HTET PGT Official Computer Science Paper - 2017
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  1. 194.24.7.255
  2. 194.24.11.255
  3. 194.23.7.255
  4. 194.24.7.250

Answer (Detailed Solution Below)

Option 1 : 194.24.7.255
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HTET PGT Official Computer Science Paper - 2019
60 Qs. 60 Marks 60 Mins

Detailed Solution

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Here, no. of mask bits = network id = n = 21

In classless addressing, no. of address are given by 232-n

For last address set 32 – n rightmost bits to 1.

 

i.e. set 11 rightmost bits to 1.

194.24.0000 0000. 0000 0000

194.24.0000 0111. 1111 1111

The last address in this network will be 194.24.7.255

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